Enthalpies of solution and hydration
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Define enthalpy change of hydration (ΔHhyd).
ΔHhyd is the enthalpy change when one mole of gaseous ions dissolves in water to form an infinitely dilute solution.
Define enthalpy change of solution (ΔHsol).
ΔHsol is the enthalpy change when one mole of a substance dissolves in water to form an infinitely dilute solution.
Draw an energy cycle that relates enthalpy change of solution, lattice energy, and enthalpy change of hydration for NaCl.
Cycle: NaCl(s) + H₂O(l) -> Na+(aq) + Cl-(aq) (ΔHsol). Alternative route: NaCl(s) -> Na+(g) + Cl-(g) (ΔHlattice) then Na+(g) + H₂O(l) -> Na+(aq) (ΔHhyd(Na+)) AND Cl-(g) + H₂O(l) -> Cl-(aq) (ΔHhyd(Cl-)). ΔHsol = ΔHlattice + ΔHhyd(Na+) + ΔHhyd(Cl-).
How does ionic charge affect the magnitude of the enthalpy change of hydration?
Higher ionic charge leads to a more negative (larger magnitude) enthalpy change of hydration. This is because more highly charged ions attract water molecules more strongly, releasing more energy.
How does ionic radius affect the magnitude of the enthalpy change of hydration?
Smaller ionic radius leads to a more negative (larger magnitude) enthalpy change of hydration. Smaller ions have a higher charge density, leading to stronger attraction to water molecules and greater energy release.
Define entropy (S).
Entropy (S) is a measure of the number of possible arrangements of particles and their energy in a system. Higher entropy corresponds to greater disorder or randomness.
Predict the sign of the entropy change (ΔS) for the boiling of water.
ΔS is positive. Boiling increases the disorder as liquid water becomes gaseous water, increasing the number of possible arrangements and energy distributions of the water molecules.
Calculate the entropy change for a reaction given standard entropies of reactants and products.
ΔS ⦵ = ΣS ⦵ (products) – ΣS ⦵ (reactants). Sum the standard entropies of all products and subtract the sum of standard entropies of all reactants, considering stoichiometric coefficients.
State the Gibbs equation.
The Gibbs equation is ΔG ⦵ = ΔH ⦵ – TΔS ⦵, where ΔG ⦵ is the Gibbs free energy change, ΔH ⦵ is the enthalpy change, T is the temperature in Kelvin, and ΔS ⦵ is the entropy change.
How does the sign of ΔG predict the feasibility of a reaction?
If ΔG is negative, the reaction is feasible (spontaneous). If ΔG is positive, the reaction is non-feasible (non-spontaneous). If ΔG is zero, the reaction is at equilibrium.
Predict the effect of increasing temperature on the feasibility of a reaction if ΔH is positive and ΔS is positive.
Increasing temperature will make the reaction more feasible (more likely to be spontaneous). Since ΔH is positive and ΔS is positive, as T increases, the -TΔS term becomes more negative, eventually making ΔG negative.
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