Ionisation energy
9 flashcards to master this topic
Define the term 'first ionisation energy'.
First ionisation energy is the energy required to remove one mole of electrons from one mole of gaseous atoms to form one mole of singly positive gaseous ions.
Write the equation representing the second ionisation energy of Magnesium.
The second ionisation energy equation for Magnesium is: Mg⁺(g) → Mg²⁺(g) + e⁻. This represents removing an electron from a Mg⁺ ion in the gaseous phase.
Explain the general trend in first ionisation energy across a period (e.g., Period 3).
Across a period, first ionisation energy generally increases due to increasing nuclear charge with similar shielding, leading to a stronger attraction between the nucleus and outer electrons. The atomic radius also decreases, further increasing the attraction.
Explain the general trend in first ionisation energy down a group (e.g., Group 1).
Down a group, first ionisation energy generally decreases due to increasing atomic radius and increased shielding by inner shells. This results in a weaker attraction between the nucleus and outer electrons.
Explain why successive ionisation energies for an element always increase.
Successive ionisation energies increase because each electron is being removed from an increasingly positive ion. This requires more energy to overcome the greater attraction between the nucleus and the remaining electrons.
List the four main factors influencing ionisation energy.
The main factors are: (1) Nuclear charge (2) Atomic/ionic radius (3) Shielding by inner shells/sub-shells (4) Spin-pair repulsion. These factors affect the strength of attraction between the nucleus and the valence electrons.
How can successive ionisation energy data be used to deduce the electronic configuration of an element?
Large jumps in successive ionisation energies indicate the removal of an electron from a new electron shell, closer to the nucleus. By counting the number of electrons removed before each large jump, the number of electrons in each shell can be determined, revealing the electronic configuration.
Explain how spin-pair repulsion affects ionisation energy.
Spin-pair repulsion occurs when two electrons occupy the same orbital. This repulsion makes it slightly easier to remove one of these electrons, resulting in a lower ionisation energy than expected compared to an electron in a singly occupied orbital.
Explain why the first ionisation energy of Aluminium is lower than that of Magnesium.
Aluminium's outer electron is in a 3p orbital, which is higher in energy and therefore further from the nucleus compared to Magnesium's 3s electrons. The 3p electron is also slightly more shielded. This makes the removal of the 3p electron easier, resulting in a lower first ionisation energy for Aluminium.
Ready to test yourself?
Practice with MCQ questions to check your understanding of Ionisation energy.
Take QuizStudy Mode
Rate each card Hard, Okay, or Easy after flipping.