Electric force between point charges
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For a uniformly charged spherical conductor, where can the entire charge be considered to be located when calculating the electric field or force outside the sphere?
For points outside the sphere, the entire charge can be considered to be located at the center of the sphere. This simplifies calculations by treating the sphere as a point charge.
State Coulomb's Law in words.
Coulomb's Law states that the electric force between two point charges is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them.
Write the formula for Coulomb's Law, defining all terms.
F = Q₁Q₂ / (4πε₀r²), where: F is the electric force, Q₁ and Q₂ are the magnitudes of the charges, r is the distance between the charges, and ε₀ is the permittivity of free space.
What is the value of the permittivity of free space (ε₀)? Include units.
The permittivity of free space (ε₀) is approximately 8.85 x 10⁻¹² C² N⁻¹ m⁻².
Two point charges, +2 μC and -4 μC, are separated by a distance of 0.5 m in a vacuum. Calculate the magnitude of the electric force between them.
Using Coulomb's Law: F = (2 x 10⁻⁶ C)(4 x 10⁻⁶ C) / (4π(8.85 x 10⁻¹² C² N⁻¹ m⁻²)(0.5 m)²) ≈ 0.288 N
How does the electric force change if the distance between two point charges is doubled?
If the distance is doubled, the electric force is reduced by a factor of four (inverse square law). F ∝ 1/r² so if r becomes 2r, F becomes F/4.
Two identical spheres carry equal charge. They are separated by a certain distance. If the charge on each sphere is doubled, how does the electric force between them change?
The electric force is quadrupled. Since the force is proportional to the product of the charges, doubling both charges results in a force that is 2*2 = 4 times larger.
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