20.3 A2 Level

Force on a moving charge

8 flashcards to master this topic

Key Concept Flip

State the direction of the force on a positive charge moving in a magnetic field.

Answer Flip

The force is perpendicular to both the velocity of the charge and the magnetic field direction. Can be determined using Fleming's Left-Hand Rule (thumb = force, first finger = field, second finger = conventional current).

Definition Flip

Write the formula for the force on a charge moving in a magnetic field and define each term.

Answer Flip

F = BQv sin θ, where F is the force (N), B is the magnetic flux density (T), Q is the charge (C), v is the velocity (m/s), and θ is the angle between the velocity and the magnetic field.

Key Concept Flip

What is the Hall voltage, and how does it arise?

Answer Flip

The Hall voltage (VH) is the voltage difference created across a conductor perpendicular to both an electric current and a magnetic field. It arises due to the Lorentz force deflecting moving charges to one side of the conductor.

Definition Flip

Give the formula for Hall Voltage and define each term.

Answer Flip

VH = BI / (ntq), where VH is the Hall voltage, B is the magnetic flux density, I is the current, n is the charge carrier density, t is the thickness of the conductor, and q is the elementary charge.

Key Concept Flip

Describe how a Hall probe is used to measure magnetic flux density.

Answer Flip

A Hall probe is placed in the magnetic field. The Hall voltage produced is proportional to the magnetic flux density. By calibrating the Hall probe with known magnetic fields, the unknown field can be determined. V ∝ B

Key Concept Flip

Describe the motion of a charged particle moving in a uniform magnetic field when its velocity is perpendicular to the field.

Answer Flip

The particle will move in a circular path. The magnetic force provides the centripetal force required for circular motion.

Calculation Flip

A proton moves at 3.0 x 10^6 m/s perpendicularly through a uniform magnetic field of 0.50 T. Calculate the magnetic force on the proton.

Answer Flip

F = BQv sin θ = (0.50 T)(1.60 x 10^-19 C)(3.0 x 10^6 m/s) sin 90° = 2.4 x 10^-13 N.

Key Concept Flip

Explain how electric and magnetic fields can be used for velocity selection of charged particles.

Answer Flip

By applying perpendicular electric and magnetic fields, only particles with a specific velocity will pass through undeflected. The electric force (F = QE) and magnetic force (F = BQv) are balanced when v = E/B.

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20.2 Force on a current-carrying conductor 20.4 Magnetic fields due to currents