Less common MM7.6

Solving Simple Differential Equations

This topic covers how to reverse the process of differentiation. Given a function for the gradient of a curve (dy/dx), you will use integration to find the equation of the original curve (y).

Part of the ESAT Mathematics 2 syllabus — revision for the Engineering and Science Admissions Test (ESAT), the UAT-UK admissions test for Cambridge, Imperial, Oxford and UCL.

Key points

  • Solving dy/dx = f(x) means finding y by integrating f(x) with respect to x.
  • The initial result of this integration is a 'general solution', which is a family of curves represented by y = F(x) + C, where F(x) is the integral of f(x) and C is an unknown constant.
  • To find a unique 'particular solution', you need an 'initial condition' – a specific point (x, y) that the curve passes through.
  • By substituting the x and y values from the initial condition into the general solution, you can solve for the constant C.

Diagram

GraphGraph with axes x and y. (0,0)(0,2)(0,-2)xy
Solving dy/dx = f(x) yields a family of curves y = F(x) + C (general solution). An initial condition (a specific point) selects one unique curve (particular solution). The diagram shows how different values of C shift the solution family vertically.

Formulae

If dy/dx = f(x), then y = ∫f(x) dx

Use this fundamental relationship when you are given the gradient function of a curve and need to find the equation of the curve itself.

Definitions

Differential Equation
An equation that relates a function with its derivatives. The form dy/dx = f(x) is a simple type of differential equation.
General Solution
The solution to a differential equation that includes an arbitrary constant of integration (+ C). It represents an entire family of functions.
Particular Solution
The specific solution obtained after using a given condition (like a point on the curve) to determine the value of the constant of integration, C.

Worked example

The gradient of a curve is given by the equation dy/dx = 6x2 + 8/x3. Given that the curve passes through the point (2, 19), find the equation for y.

  1. 1

    First, rewrite the gradient function using negative indices for easier integration:

    dy/dx = 6x2 + 8x-3
  2. 2

    Integrate the function with respect to x to find the general solution for y:

    y = ∫(6x2 + 8x-3) dx
  3. 3

    Apply the power rule for integration (∫axn dx = a(x^(n+1))/(n+1)):

    y = (6x3)/3 + (8x-2)/-2 + C
  4. 4

    Simplify the expression:

    y = 2x3 - 4x-2 + C
  5. 5

    Use the given point (2, 19) to find the constant C.

    Substitute x=2 and y=19 into the equation
  6. 6
    19 = 2(2)3 - 4(2)-2 + C
  7. 7

    Calculate the powers:

    19 = 2(8) - 4(1/4) + C
  8. 8

    Simplify the arithmetic:

    19 = 16 - 1 + C, which gives 19 = 15 + C
  9. 9

    Solve for C:

    C = 4
  10. 10

    Substitute C back into the general solution to get the particular solution:

    y = 2x3 - 4x-2 + 4

Answer: y = 2x3 - 4/x2 + 4

Common mistakes

  • ×Forgetting to include the constant of integration, '+ C', after integrating. This is the most common error.
  • ×Making arithmetic mistakes when substituting coordinates to find C, especially with negative numbers or fractions.
  • ×Incorrectly applying the power rule for integration to negative powers, for example, thinking the integral of x-3 is proportional to x-4 instead of x-2.

No-calculator tips

  • When finding C, calculate the numerical part of the equation first, then rearrange to find C. For example, in `19 = 2(8) - 4(1/4) + C`, first calculate `16 - 1 = 15` to get `19 = 15 + C`.
  • Always rewrite terms like `k/xn` as `kx-n` before integrating. It makes applying the power rule much more straightforward and less error-prone.
  • As a final check, mentally differentiate your final answer for y. It should return you to the original expression for dy/dx. This verifies your integration was correct.

Read this topic in the official UAT-UK ESAT guide →

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