SL & HL Wave Behaviour BETA C.2

Wave Model

This topic explores the fundamental wave model, analyzing how transverse and longitudinal waves transport energy through oscillations. It covers key wave relationships and examines the distinct properties of mechanical sound waves and electromagnetic radiation.

Part of IB Physics (2025-2030 syllabus) — Standard and Higher Level.

Key points

  • Waves are oscillations that transfer energy and information from one location to another without transferring matter.
  • In transverse waves, the oscillations of the particles or fields are perpendicular to the direction of energy propagation (e.g., electromagnetic waves, water waves).
  • In longitudinal waves, the oscillations of the particles are parallel to the direction of energy propagation, creating regions of compression and rarefaction (e.g., sound waves).
  • The physical properties of a wave are mathematically linked by its speed (vv), frequency (ff), period (TT), and wavelength (λ\lambda).
  • Sound waves require a physical medium to propagate, whereas electromagnetic waves are self-propagating oscillations of electric and magnetic fields that can travel through a vacuum.
  • All regions of the electromagnetic spectrum travel at the same speed c=3.00×108 m s1c = 3.00 \times 10^8\ \text{m s}^{-1} in a vacuum, so a higher frequency always corresponds to a shorter wavelength.

Subtopic by subtopic

Transverse and longitudinal waves

A wave is a periodic disturbance that carries energy and information from one place to another without any net transfer of matter. Waves are classified by comparing the direction of oscillation with the direction of energy propagation.

In a transverse wave the oscillations are perpendicular to the direction the energy travels: waves on a stretched string, ripples on a water surface and all electromagnetic waves behave this way, showing alternating crests and troughs.

In a longitudinal wave the oscillations are parallel to the energy direction, so the medium is alternately squeezed into compressions and stretched into rarefactions; sound in air is the standard example.

A slinky spring demonstrates both types: flicking one end side to side sends a transverse pulse along it, while pushing and pulling along its length sends a longitudinal pulse.

You should be able to:

  • define both wave types
  • classify given examples
  • sketch and label each profile (crest, trough, compression, rarefaction)
  • explain that in both cases it is energy, not matter, that moves along the wave

Wavelength, frequency, period and wave speed

Four quantities describe any periodic wave:

  • the wavelength λ\lambda is the shortest distance between two points oscillating in phase
  • the frequency ff is the number of cycles passing a point each second
  • the period T=1fT = \frac{1}{f} is the time for one complete cycle
  • the amplitude is the maximum displacement from equilibrium

Because exactly one wavelength passes a fixed point during one period, the wave speed is:

v=fλ=λTv = f\lambda = \frac{\lambda}{T}

These quantities are read from two different graphs. A displacement-distance graph is a snapshot of the whole wave at one instant, so its repeat length is λ\lambda; a displacement-time graph follows a single point, so its repeat interval is TT.

As a concrete example, a water wave with f=2.0 Hzf = 2.0\ \text{Hz} and λ=0.75 m\lambda = 0.75\ \text{m} travels at v=2.0×0.75=1.5 m s1v = 2.0 \times 0.75 = 1.5\ \text{m s}^{-1}.

You must be able to:

  • rearrange v=fλv = f\lambda fluently
  • convert unit prefixes such as kHz\text{kHz} and ms\text{ms} before substituting
  • extract λ\lambda, TT and amplitude from the correct type of graph

Sound waves

Sound is a longitudinal mechanical wave. A vibrating source, such as a loudspeaker cone or a tuning fork, pushes repeatedly on the air particles next to it, and energy is then passed forward by particle collisions. This creates travelling regions of high density and pressure (compressions) separated by regions of low density and pressure (rarefactions).

Because the mechanism depends entirely on particles colliding, propagation is impossible in a vacuum: a ringing bell inside an evacuated jar falls silent even though it is still visibly vibrating.

The speed of sound depends on the medium:

  • roughly 340 m s1340\ \text{m s}^{-1} in air at room temperature
  • faster in liquids
  • fastest in solids, where the particles are most strongly coupled

The frequency of a sound determines its pitch and the amplitude its loudness; a typical human ear responds between about 20 Hz20\ \text{Hz} and 20 kHz20\ \text{kHz}. The few-second gap between seeing lightning and hearing thunder is an everyday consequence of this finite speed.

You should be able to:

  • explain the propagation mechanism in terms of compressions and rarefactions
  • justify why sound cannot cross a vacuum
  • apply v=fλv = f\lambda to sound problems

Electromagnetic waves

Electromagnetic waves are transverse waves in which oscillating electric and magnetic fields, perpendicular both to each other and to the direction of travel, carry energy without needing any medium.

The mechanism is a self-sustaining loop: a time-varying electric field generates a perpendicular magnetic field, which in turn regenerates the electric field, so the wave drives itself through empty space at the universal speed c=3.00×108 m s1c = 3.00 \times 10^8\ \text{m s}^{-1}.

The electromagnetic spectrum is the family of these waves ordered by wavelength:

  • radio waves
  • microwaves
  • infrared
  • visible light (from about 400 nm400\ \text{nm} at the violet end to 700 nm700\ \text{nm} at the red end)
  • ultraviolet
  • X-rays
  • gamma rays

All regions travel at the same speed cc in a vacuum, so a higher frequency always means a shorter wavelength through:

c=fλc = f\lambda

When an electromagnetic wave enters a medium such as glass, its speed and wavelength decrease while its frequency stays fixed by the source.

You should be able to:

  • list the spectrum regions in order
  • recall the visible wavelength range
  • calculate any one of frequency, wavelength or speed from the other two

Formulae

v=fλv = f\lambda

To calculate wave speed, frequency, or wavelength when the other two quantities are known.

T=1fT = \frac{1}{f}

To convert between the period of an oscillation and its frequency.

Definitions

Wavelength (λ\lambda)
The shortest distance between two points on a wave that are in phase with one another, such as from crest to crest or compression to compression.
Frequency (ff)
The number of complete wave cycles or oscillations that pass a given point per unit time, measured in hertz (Hz\text{Hz}).
Period (TT)
The time taken for one complete oscillation of a particle in the wave, equal to the reciprocal of the frequency.
Wavefront
A line or surface representing corresponding points of a wave that vibrate in phase.
Amplitude
The maximum displacement of a point on the wave from its equilibrium position; for sound, a larger amplitude means a louder sound.

Worked examples

1

A sound wave travels through air at a speed of 340 m s1340\ \text{m s}^{-1}. A tuning fork vibrating at a frequency of 2.5 kHz2.5\ \text{kHz} excites this sound wave. Calculate the wavelength of the sound wave produced.

  1. 1
    State the known variables: speed v=340 m s1v = 340\ \text{m s}^{-1} and frequency f=2.5 kHz=2.5×103 Hzf = 2.5\ \text{kHz} = 2.5 \times 10^3\ \text{Hz}.
  2. 2
    Recall the wave equation: v=fλv = f\lambda.
  3. 3
    Rearrange the equation to solve for wavelength: λ=vf\lambda = \frac{v}{f}.
  4. 4
    Substitute the values into the equation: λ=3402.5×103\lambda = \frac{340}{2.5 \times 10^3}.
  5. 5
    Calculate the final value: λ=0.136 m\lambda = 0.136\ \text{m}.

Answer: 0.14 m0.14\ \text{m}

2

An electromagnetic wave of frequency 5.0×1014 Hz5.0 \times 10^{14}\ \text{Hz} travels from a vacuum into a glass block where its speed drops to 2.0×108 m s12.0 \times 10^8\ \text{m s}^{-1}. Determine the change in wavelength of the wave as it enters the glass.

  1. 1
    Recall that the frequency of a wave is determined by its source and remains constant (f=5.0×1014 Hzf = 5.0 \times 10^{14}\ \text{Hz}) when transitioning between media.
  2. 2
    Calculate the wavelength in vacuum (λvacuum\lambda_{\text{vacuum}}) using the speed of light in vacuum c=3.0×108 m s1c = 3.0 \times 10^8\ \text{m s}^{-1}: λvacuum=cf=3.0×1085.0×1014=6.0×107 m\lambda_{\text{vacuum}} = \frac{c}{f} = \frac{3.0 \times 10^8}{5.0 \times 10^{14}} = 6.0 \times 10^{-7}\ \text{m}.
  3. 3
    Calculate the wavelength in glass (λglass\lambda_{\text{glass}}) using the wave speed in glass v=2.0×108 m s1v = 2.0 \times 10^8\ \text{m s}^{-1}: λglass=vf=2.0×1085.0×1014=4.0×107 m\lambda_{\text{glass}} = \frac{v}{f} = \frac{2.0 \times 10^8}{5.0 \times 10^{14}} = 4.0 \times 10^{-7}\ \text{m}.
  4. 4
    Calculate the change in wavelength: the wavelength decreases by Δλ=λvacuumλglass=6.0×107 m4.0×107 m=2.0×107 m|\Delta\lambda| = \lambda_{\text{vacuum}} - \lambda_{\text{glass}} = 6.0 \times 10^{-7}\ \text{m} - 4.0 \times 10^{-7}\ \text{m} = 2.0 \times 10^{-7}\ \text{m}.

Answer: a decrease of 2.0×107 m2.0 \times 10^{-7}\ \text{m}

3

An FM radio station broadcasts an electromagnetic wave at a frequency of 98.0 MHz98.0\ \text{MHz}. Calculate (a) the period of the wave and (b) its wavelength in air.

  1. 1
    Convert the frequency to SI units: f=98.0 MHz=9.80×107 Hzf = 98.0\ \text{MHz} = 9.80 \times 10^{7}\ \text{Hz}.
  2. 2
    Calculate the period using T=1f=19.80×107=1.02×108 sT = \frac{1}{f} = \frac{1}{9.80 \times 10^{7}} = 1.02 \times 10^{-8}\ \text{s}.
  3. 3
    Recall that radio waves are electromagnetic, so in air they travel at approximately c=3.00×108 m s1c = 3.00 \times 10^8\ \text{m s}^{-1}.
  4. 4
    Rearrange the wave equation to find the wavelength: λ=cf=3.00×1089.80×107\lambda = \frac{c}{f} = \frac{3.00 \times 10^8}{9.80 \times 10^{7}}.
  5. 5
    Evaluate the result: λ=3.06 m\lambda = 3.06\ \text{m}.

Answer: T=1.02×108 sT = 1.02 \times 10^{-8}\ \text{s}; λ=3.06 m\lambda = 3.06\ \text{m}

Common mistakes

  • ×Confusing displacement-distance graphs with displacement-time graphs. A displacement-distance graph is a spatial snapshot showing wavelength (λ\lambda), whereas a displacement-time graph shows the history of a single point, revealing the period (TT).
  • ×Believing that wave frequency changes when a wave enters a different medium. The frequency is determined solely by the source; only speed and wavelength change.
  • ×Incorrectly assuming that sound can travel through a vacuum. Sound is a mechanical wave and requires a physical medium to transmit its longitudinal compressions.

Exam tips

  • When asked to **distinguish** between transverse and longitudinal waves, explicitly define the orientation of particle or field oscillations relative to the direction of energy propagation.
  • Always **check** the unit prefixes on axes (e.g., milliseconds on a time axis or millimeters on a displacement axis) before substituting values into v=fλv = f\lambda.
  • Be prepared to **sketch** the wave profiles of both transverse and longitudinal waves, clearly marking regions of compression and rarefaction for the latter.

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