4.3 BETA

Scale drawings

4 learning objectives 2 core 2 extended

1. Overview

Scale drawings are used to accurately represent real-world objects and distances on a smaller scale, such as on maps or architectural plans. They rely on maintaining correct proportions using a scale factor. This topic covers interpreting and creating scale drawings, working with three-figure bearings for direction, and understanding how scales affect lengths and areas. A firm grasp of ratios, unit conversions, and basic geometry is essential for success.


Key Definitions

  • Scale: The ratio that defines the relationship between the distance on a map or drawing and the actual distance in real life.
  • Ratio Scale: A scale written in the form 1:n1 : n, where 1 unit on the drawing represents nn units in real life (both must be the same units).
  • Bearing: A measure of direction expressed as an angle in degrees, measured clockwise from North.
  • Three-figure Bearing: A bearing written using three digits (e.g., 045045^\circ instead of 4545^\circ).
  • North Line: A vertical line drawn on a map pointing towards the North pole, used as the 000000^\circ reference point.

Core Content

A. Interpreting and Using Scales

Scales are usually given as a ratio, such as 1:50,0001 : 50,000. This means 1 cm1\text{ cm} on the map represents 50,000 cm50,000\text{ cm} in real life.

Conversion Tip: To convert between map units and real-world units, remember:

  • 1 km=1,000 m1\text{ km} = 1,000\text{ m}
  • 1 m=100 cm1\text{ m} = 100\text{ cm}
  • Therefore, 1 km=100,000 cm1\text{ km} = 100,000\text{ cm}

Worked Example 1 — Finding Actual Distance

A map has a scale of 1:20,0001 : 20,000. The distance between two towns on the map is 8.5 cm8.5\text{ cm}. Calculate the actual distance in kilometers.

  1. State the given information: Scale: 1:20,0001 : 20,000 Map distance: 8.5 cm8.5\text{ cm}

  2. Multiply map distance by the scale factor: 8.5×20,000=170,000 cm8.5 \times 20,000 = 170,000\text{ cm} Reason: To find the actual distance in cm.

  3. Convert cm to meters (divide by 100): 170,000÷100=1,700 m170,000 \div 100 = 1,700\text{ m} Reason: There are 100 cm in 1 meter.

  4. Convert meters to kilometers (divide by 1,000): 1,700÷1,000=1.7 km1,700 \div 1,000 = 1.7\text{ km} Reason: There are 1,000 meters in 1 kilometer.

Final Answer: 1.7 km1.7\text{ km}

Worked Example 2 — Finding Map Distance

The actual distance between two cities is 45 km45\text{ km}. A map has a scale of 1:500,0001 : 500,000. What is the distance between the two cities on the map, in centimeters?

  1. State the given information: Scale: 1:500,0001 : 500,000 Actual distance: 45 km45\text{ km}

  2. Convert the actual distance to centimeters: 45 km=45×1,000 m=45,000 m45\text{ km} = 45 \times 1,000\text{ m} = 45,000\text{ m} Reason: Convert km to meters. 45,000 m=45,000×100 cm=4,500,000 cm45,000\text{ m} = 45,000 \times 100\text{ cm} = 4,500,000\text{ cm} Reason: Convert meters to centimeters.

  3. Set up a proportion: 1500,000=Map Distance4,500,000\frac{1}{500,000} = \frac{\text{Map Distance}}{4,500,000} Reason: Express the scale as a fraction.

  4. Solve for the map distance: Map Distance=4,500,000500,000=9 cm\text{Map Distance} = \frac{4,500,000}{500,000} = 9\text{ cm} Reason: Multiply both sides by 4,500,000.

Final Answer: 9 cm9\text{ cm}

B. Three-Figure Bearings

Bearings must follow three strict rules:

  1. Measured from North.
  2. Measured Clockwise.
  3. Written with three digits (e.g., 005,072,210005^\circ, 072^\circ, 210^\circ).
📊A point A with a vertical North line. An arrow rotates clockwise from the North line to a point B. The angle between North and the line AB is labeled 060060^\circ.

Worked Example 3 — Drawing a Bearing

Draw the position of point YY from point XX on a bearing of 120120^\circ at a distance of 5 cm5\text{ cm}.

  1. Mark point XX and draw a vertical North line.
  2. Place the center of the protractor on XX with the 00^\circ line aligned with the North line.
  3. Measure 120120^\circ clockwise and mark a point.
  4. Draw a line from XX through the mark exactly 5 cm5\text{ cm} long.
  5. Label the end of the line YY.

Worked Example 4 — Measuring a Bearing

Point BB is located southeast of point AA. A North line is drawn at point AA. Using a protractor, the angle measured clockwise from the North line at AA to point BB is 135135^\circ. State the three-figure bearing of BB from AA.

  1. Identify the given information: Angle measured clockwise from North at AA to BB: 135135^\circ

  2. Express the bearing as a three-figure bearing: Since the angle is 135135^\circ, the three-figure bearing is 135135^\circ.

Final Answer: 135135^\circ


Extended Content (Extended Only)

A. Area Scale Factors

When a scale is 1:n1 : n, it refers to lengths. For areas, the scale factor must be squared (1:n21 : n^2). This is because area is a two-dimensional measurement, so both the length and width are scaled by the linear scale factor.

Worked Example 5 — Calculating Actual Area

A map has a scale of 1:5,0001 : 5,000. A forest on the map has an area of 12 cm212\text{ cm}^2. Calculate the actual area of the forest in square meters (m2\text{m}^2).

  1. State the given information: Scale: 1:5,0001 : 5,000 Map area: 12 cm212\text{ cm}^2

  2. Find the linear scale factor in meters: 1 cm:5,000 cm1\text{ cm} : 5,000\text{ cm} 1 cm:50 m1\text{ cm} : 50\text{ m} Reason: Divide 5,000 cm by 100 to convert to meters.

  3. Square the scale factor for area: (1 cm)2:(50 m)2(1\text{ cm})^2 : (50\text{ m})^2 1 cm2:2,500 m21\text{ cm}^2 : 2,500\text{ m}^2 Reason: Area scale factor is the square of the linear scale factor.

  4. Multiply map area by the area scale factor: 12×2,500=30,000 m212 \times 2,500 = 30,000\text{ m}^2 Reason: To find the actual area.

Final Answer: 30,000 m230,000\text{ m}^2

B. Back Bearings (Reverse Bearings)

To find the bearing of AA from BB when given the bearing of BB from AA:

  • If the bearing is less than 180180^\circ, add 180180^\circ.
  • If the bearing is more than 180180^\circ, subtract 180180^\circ.
📊Two parallel North lines at points A and B. A line connects them. Show that the interior angles between parallel lines add to 180180^\circ, explaining why the ±180\pm 180^\circ rule works.

Worked Example 6 — Calculating Back Bearing

The bearing of town BB from town AA is 065065^\circ. Calculate the bearing of town AA from town BB.

  1. State the given information: Bearing of BB from AA: 065065^\circ

  2. Apply the back bearing rule: Since 065<180065^\circ < 180^\circ, add 180180^\circ. 065+180=245065^\circ + 180^\circ = 245^\circ

Final Answer: 245245^\circ

Worked Example 7 — Calculating Back Bearing (Alternative)

The bearing of a ship from a lighthouse is 280280^\circ. Find the bearing of the lighthouse from the ship.

  1. State the given information: Bearing of ship from lighthouse: 280280^\circ

  2. Apply the back bearing rule: Since 280>180280^\circ > 180^\circ, subtract 180180^\circ. 280180=100280^\circ - 180^\circ = 100^\circ

Final Answer: 100100^\circ


Key Equations

  • Scale Ratio: 1:n=Drawing LengthActual Length1 : n = \frac{\text{Drawing Length}}{\text{Actual Length}}
  • Area Scale Factor: (Linear Scale)2(\text{Linear Scale})^2
  • Volume Scale Factor: (Linear Scale)3(\text{Linear Scale})^3
  • Back Bearing: x±180x \pm 180^\circ

Formula Sheet Note: These formulas are not provided on the IGCSE formula sheet. You must memorize the conversion factors and the area/volume rules.


Common Mistakes to Avoid

  • Wrong: Writing a bearing as 4545^\circ. ✓ Right: Always use three digits for bearings: 045045^\circ.
  • Wrong: Using the length scale factor to convert area (e.g., multiplying 12 cm212\text{ cm}^2 by 5,0005,000 instead of 5,00025,000^2). ✓ Right: Always square the scale factor before applying it to an area.
  • Wrong: Confusing "Bearing of AA from BB" with "Bearing of BB from AA". ✓ Right: Put your pencil on the point following the word "from"—that is where your North line and protractor go.
  • Wrong: Skipping unit conversions and getting huge, unrealistic numbers. For example, assuming a map distance of 5 cm represents 5 km directly when the scale is 1:1000. ✓ Right: Convert cm to km early in the calculation or use the 100,000100,000 conversion factor carefully.
  • Wrong: Rounding intermediate calculations and then using the rounded value in subsequent steps. ✓ Right: Keep exact values throughout the calculation and only round the final answer if necessary.

Exam Tips

  • Command Words:
    • "Measure": Use your ruler or protractor physically on the paper.
    • "Calculate": Use the numbers given; do not rely on your own measurements unless the diagram is "to scale".
  • Calculator vs Non-Calculator: In non-calculator papers, scale factors are often simple multiples (like 200200 or 500500). In calculator papers, expect values like 1:25,0001 : 25,000.
  • Accuracy Marks: IGCSE markers allow a small margin of error for measurements (usually ±2 mm\pm 2\text{ mm} for length and ±2\pm 2^\circ for bearings), but you will lose marks if your lines are not sharp or your protractor is misaligned.
  • The "1 : n" Form: If asked to give a scale in the form 1:n1 : n, ensure the "1" has no units and nn is calculated by dividing the real distance (in cm) by the map distance (in cm).

Frequently Asked Questions: Scale drawings

What is Scale in Scale drawings?

Scale: The ratio that defines the relationship between the distance on a map or drawing and the actual distance in real life.

What is Ratio Scale in Scale drawings?

Ratio Scale: A scale written in the form 1 : n, where 1 unit on the drawing represents n units in real life (both must be the same units).

What is Bearing in Scale drawings?

Bearing: A measure of direction expressed as an angle in degrees, measured clockwise from North.

What is Three-figure Bearing in Scale drawings?

Three-figure Bearing: A bearing written using three digits (e.g., 045^\circ instead of 45^\circ).

What is North Line in Scale drawings?

North Line: A vertical line drawn on a map pointing towards the North pole, used as the 000^\circ reference point.

What are common mistakes students make about Scale drawings?

Common mistake: Writing a bearing as 45^\circ. → Correct: Always use three digits for bearings: 045^\circ. Common mistake: Using the length scale factor to convert area (e.g., multiplying 12\text{ cm}^2 by 5,000 instead of 5,000^2). → Correct: Always square the scale factor before applying it to an area.