Action and use of circuit components
6 flashcards to master Action and use of circuit components
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A resistor has a constant current of 0.5 A flowing through it. If the resistance of the resistor is 10 ohms, calculate the potential difference across the resistor.
Formula: V = IR
Calculation: V = 0.5 A * 10 ohms = 5 V
Answer: The potential difference across the resistor is 5 V. Explanation: Ohm's Law states that voltage is directly proportional to the product of current and resistance.
State what happens to the potential difference across a conductor if its resistance increases, assuming the current flowing through it remains constant.
The potential difference across the conductor increases. Explanation: According to Ohm's Law (V=IR), if the resistance (R) increases while the current (I) remains constant, the potential difference (V) must also increase to maintain the equality.
A potential divider circuit consists of a 12V battery connected in series with a 200Ω resistor and a variable resistor. The variable resistor is adjusted so that its resistance is 300Ω. Calculate the voltage across the 200Ω resistor.
V = IR. First calculate the total resistance: R_total = 200Ω + 300Ω = 500Ω. Then calculate the current: I = V/R = 12V / 500Ω = 0.024A. Finally, calculate the voltage across the 200Ω resistor: V = IR = 0.024A * 200Ω = 4.8V. The voltage across the 200Ω resistor is 4.8V.
Describe how a variable potential divider can be used to control the voltage supplied to a component, such as a lamp.
A variable potential divider uses a variable resistor to split the voltage from a power supply. By adjusting the position of the sliding contact on the variable resistor, the proportion of the total resistance across which the lamp is connected changes. This alters the voltage across the lamp. Moving the slider towards one end of the resistor increases the voltage across that section, thus increasing the voltage supplied to the lamp. Moving the slider towards the other end decreases the voltage across the lamp.
Two resistors, 300 Ω and 500 Ω, are connected in series to a 12V power supply. Calculate the voltage across the 300 Ω resistor.
Formula: V₁ = (R₁ / (R₁ + R₂)) * V_in
Calculation: V₁ = (300 / (300 + 500)) * 12V = (300/800) * 12V = 0.375 * 12V = 4.5V
Answer: The voltage across the 300 Ω resistor is 4.5V. This is because the voltage divides proportionally to the resistance.
Explain how a potential divider circuit allows you to obtain a voltage that is lower than the voltage of the power supply. Relate your answer to the resistance values in the circuit.
A potential divider uses resistors in series to 'divide' the input voltage. The voltage across each resistor is proportional to its resistance. The higher the resistance of a resistor compared to the total resistance, the greater the proportion of the input voltage that will appear across it. Therefore, by using a resistor network, the voltage across a single resistor will always be lower than the total supply voltage unless that resistor comprises the whole resistance in the circuit.
About Action and use of circuit components (4.3.3)
These 6 flashcards cover everything you need to know about Action and use of circuit components for your Cambridge IGCSE Physics (0625) exam. Each card is designed based on the official syllabus requirements.
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After mastering Action and use of circuit components, explore these related topics:
- 4.3.2 Series and parallel circuits - 24 flashcards
- 4.4 Electrical safety - 10 flashcards
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