Power
2 flashcards to master Power
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An electric motor lifts a 2.0 kg mass vertically by 0.50 m in 1.0 s at a constant speed. Calculate the power output of the motor.
Power = Work Done / Time
Work Done = Force x Distance = Weight x Distance
Weight = mass x g = 2.0 kg x 9.8 N/kg = 19.6 N
Work Done = 19.6 N x 0.50 m = 9.8 J
Power = 9.8 J / 1.0 s = 9.8 W
Therefore, the power output of the motor is 9.8 Watts. Power is the rate at which work is done.
A light bulb is rated at 60 W. State what this means in terms of energy transfer.
A 60W light bulb transfers 60 Joules of electrical energy to light and heat energy every second. Power is the rate of energy transfer, so a higher wattage means more energy is transferred per second.
About Power (1.7.4)
These 2 flashcards cover everything you need to know about Power for your Cambridge IGCSE Physics (0625) exam. Each card is designed based on the official syllabus requirements.
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After mastering Power, explore these related topics:
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