3.4

Sound

24 flashcards to master Sound

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Key Concept Flip

Describe how a loudspeaker produces sound.

Answer Flip

A loudspeaker contains a cone connected to a coil of wire. An alternating current flows through the coil, creating a varying magnetic field. This field interacts with a permanent magnet, causing the cone to vibrate. The vibrating cone pushes air particles, creating compressions and rarefactions, which propagate as sound waves.

Key Concept Flip

A tuning fork vibrates at 440 Hz. State what causes the sound produced by the tuning fork.

Answer Flip

The sound produced by the tuning fork is caused by the vibrating tines of the fork. These vibrations cause the surrounding air molecules to vibrate at the same frequency, creating sound waves.

Key Concept Flip

Describe how a sound wave is longitudinal. Include how the particles of the medium move relative to the direction of energy transfer. (2 marks)

Answer Flip

A longitudinal wave is a wave in which the particles of the medium vibrate parallel to the direction in which the wave travels. This means the particles oscillate back and forth along the same line as the energy is being transferred. The sound wave comprises areas of compression (high pressure) and rarefaction (low pressure) along this line.

Key Concept Flip

State the direction of particle oscillation in relation to the direction of energy transfer in a sound wave. (1 mark)

Answer Flip

Particles oscillate parallel to the direction of energy transfer.

Key Concept Flip

State the approximate range of frequencies audible to the average human.

Answer Flip

The approximate range of audible frequencies for humans is 20 Hz to 20000 Hz. This represents the lower and upper limits of sound that a typical person can hear.

Key Concept Flip

A particular sound wave has a frequency of 15 Hz. Is this sound wave likely to be audible to a typical human? Explain your answer.

Answer Flip

No, the sound wave is unlikely to be audible to a typical human.
The audible range for humans is approximately 20 Hz to 20000 Hz. Since 15 Hz is below the lower limit of this range, most people would not be able to hear it.

Key Concept Flip

Explain why you cannot hear sounds in a vacuum.

Answer Flip

Sound waves are mechanical waves, meaning they require a medium (like air, water, or solids) to travel. A vacuum is a space devoid of matter, therefore, there is no medium for the sound waves to propagate. Without a medium to vibrate, sound cannot be transmitted.

Key Concept Flip

State the type of wave that sound is, and describe why a medium is needed for it to travel.

Answer Flip

Sound is a longitudinal wave. A medium is needed because the wave is propagated by vibrations of the particles within the medium. Without particles, there's nothing to vibrate, and the sound cannot travel.

Key Concept Flip

Calculate the distance a sound wave travels in air in 5 seconds, given the speed of sound in air is 340 m/s.

Answer Flip

Distance = Speed x Time
Distance = 340 m/s x 5 s
Distance = 1700 m

Sound travels at a constant speed (in constant conditions). Distance is calculated by multiplying speed by time.

Key Concept Flip

State a typical value for the speed of sound in air.

Answer Flip

A typical value for the speed of sound in air is 340 m/s.

The speed can vary slightly with temperature and humidity, but this is a good approximation.

Key Concept Flip

Describe how a sound wave travelling through air creates regions of compression and rarefaction.

Answer Flip

Compressions are regions where air particles are forced closer together, resulting in increased density and pressure. Rarefactions are regions where air particles are spread further apart, resulting in decreased density and pressure. The vibrating source causes the air particles to oscillate back and forth, creating these alternating regions of high and low pressure that propagate as the sound wave.

Key Concept Flip

State whether the density of air particles is higher in a compression or a rarefaction.

Answer Flip

The density of air particles is higher in a compression. A compression is a region where air particles are pushed closer together, increasing the density relative to the undisturbed air.

Key Concept Flip

Sound travels through steel at 5000 m/s, through water at 1500 m/s and through air at 340 m/s. A hammer strikes a steel railway track. Calculate how much longer it takes for the sound to reach a listener 1 km away through the air compared to through the steel.

Answer Flip

Time = Distance / Speed
Time through steel = 1000 m / 5000 m/s = 0.2 s
Time through air = 1000 m / 340 m/s = 2.94 s
Time difference = 2.94 s - 0.2 s = 2.74 s
Answer: 2.74 s. Sound travels much faster through steel due to the closer packing of the molecules.

Key Concept Flip

State, in order from fastest to slowest, the typical relative speeds of sound through solids, liquids, and gases. Explain why this is the general trend.

Answer Flip

Solids > Liquids > Gases
Explanation: Sound travels as a wave of vibrations. The closer the molecules are to each other, the faster the vibrations can be passed along. Molecules are closest in solids, further apart in liquids, and furthest apart in gases. Therefore, sound generally travels fastest in solids, then liquids, and slowest in gases.

Key Concept Flip

A student stands 100 meters from a large wall and claps. The echo returns 0.6 seconds later. Calculate the speed of sound in air.

Answer Flip

Speed = Distance / Time
Since the sound travels to the wall AND back, the total distance is 2 * 100m = 200m
Speed = 200m / 0.6s = 333.33 m/s

Answer: 333.33 m/s (approximately)

Explanation: The sound travels to the wall and back, therefore we double the distance.

Key Concept Flip

Describe a method, involving a measurement of distance and time, to determine the speed of sound in air using a starting pistol and a stopwatch.

Answer Flip

1. Two observers are needed, A and B.
2. Measure a large distance (

Example: 300m) between observer A and observer B using a measuring tape.<br>3. Observer A fires a starting pistol. Observer B starts the stopwatch when they see the smoke from the pistol. They stop the stopwatch when they hear the sound of the pistol.<br>4. Record the time taken (t) for the sound to travel from A to B.<br>5. Calculate the speed of sound using the formula: Speed = Distance / Time.<br>6. Repeat the experiment several times and calculate the average speed of sound to improve accuracy.
Key Concept Flip

The amplitude of a sound wave is doubled, while the frequency remains constant. If the original sound had a loudness level of 50 dB, describe the effect on the loudness of the sound.

Answer Flip

The loudness of the sound will increase. Doubling the amplitude of a sound wave significantly increases its intensity. While the relationship between amplitude and loudness is not linear, a doubling of amplitude results in a perceived increase in loudness. The new loudness will be perceived to be louder.

Key Concept Flip

State how an increase in the frequency of a sound wave affects its pitch.

Answer Flip

An increase in the frequency of a sound wave increases its pitch. Higher frequency sounds are perceived as higher pitched sounds, and lower frequency sounds are perceived as lower pitched sounds.

Key Concept Flip

Describe how an echo is formed.

Answer Flip

An echo is formed when a sound wave travels from a source to a distant surface. The sound wave then reflects off the surface and travels back to the source. This returning, reflected sound wave is the echo.

Key Concept Flip

A student shouts towards a cliff and hears an echo 1.5 seconds later. State what process causes this echo.

Answer Flip

The echo is caused by the reflection of the sound wave from the cliff face.

Definition Flip

Define ultrasound.

Answer Flip

Ultrasound is sound with a frequency higher than 20 kHz.

Key Concept Flip

State a frequency that would be classified as ultrasound.

Answer Flip

Any frequency higher than 20 kHz.

Example: 25 kHz.
Key Concept Flip

Ultrasound is used to detect flaws in a metal pipe. An ultrasound pulse is sent into the pipe, and an echo from a flaw is detected 0.0002 seconds later. If the speed of ultrasound in the pipe is 5000 m/s, calculate the distance of the flaw from the ultrasound source.

Answer Flip

Distance = speed x time. Since the pulse travels to the flaw AND back, we must halve the time.
Distance = 5000 m/s * (0.0002 s / 2) = 0.5 m
The flaw is 0.5 meters from the source.

Key Concept Flip

Explain how ultrasound is used in medical scanning to create an image of soft tissue.

Answer Flip

Ultrasound pulses are emitted into the body. When the ultrasound reaches a boundary between different tissues, some of the ultrasound is reflected. The reflected pulses are detected, and the time taken for the echoes to return is used to determine the depth of the tissue boundary. The intensity of the reflected pulses provides information about the nature of the tissue. This information is then used to build up an image.

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3.3 Electromagnetic spectrum 4.1 Simple phenomena of magnetism

Key Questions: Sound

Define ultrasound.

Ultrasound is sound with a frequency higher than 20 kHz.

About Sound (3.4)

These 24 flashcards cover everything you need to know about Sound for your Cambridge IGCSE Physics (0625) exam. Each card is designed based on the official syllabus requirements.

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