Specific heat capacity
8 flashcards to master Specific heat capacity
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A 50g block of aluminium absorbs 450J of energy. Calculate the rise in temperature of the aluminium block. (Specific heat capacity of aluminium = 900 J/kg°C)
ΔT = Q / (m * c)
ΔT = 450 J / (0.05 kg * 900 J/kg°C)
ΔT = 10°C
The rise in temperature is calculated by dividing the energy absorbed by the product of the mass and specific heat capacity. This relationship stems from the definition of specific heat capacity.
Explain, using the concept of internal energy, why heating a metal block causes its temperature to increase.
Heating a metal block increases the kinetic energy of its constituent particles (atoms or molecules). This increased kinetic energy corresponds to an increase in the block's internal energy. Temperature is a measure of the average kinetic energy of these particles. Therefore, an increase in internal energy, due to the increased kinetic energy of the particles, results in a rise in the block's temperature.
Explain how an increase in temperature of a copper block relates to the kinetic energy of its particles.
As the temperature of the copper block increases, the average kinetic energy of the copper atoms increases. This means the copper atoms vibrate more vigorously around their fixed positions in the lattice structure. The higher the temperature, the greater the average kinetic energy and the faster the vibrations.
Describe how the average kinetic energy of particles within a substance changes as its temperature increases. Use the terms 'motion' and 'temperature' in your answer.
As temperature increases, the average kinetic energy of the particles increases. This means the particles move faster (translational, rotational, or vibrational motion, depending on the state of matter). Temperature is a measure of the average kinetic energy of the particles.
Define specific heat capacity.
Specific heat capacity is the energy required per unit mass per unit temperature increase. It is the amount of energy needed to raise the temperature of 1 kg of a substance by 1 °C (or 1 K).
A 0.5 kg block of aluminum absorbs 10,000 J of heat energy. If the initial temperature of the block was 20°C, and the specific heat capacity of aluminum is 900 J/(kg°C), calculate the final temperature of the block.
Formula: ΔE = mcΔθ
Rearrange for Δθ: Δθ = ΔE / (mc)
Δθ = 10000 J / (0.5 kg * 900 J/(kg°C))
Δθ = 22.22 °C
Final temperature = Initial temperature + Δθ
Final temperature = 20°C + 22.22°C = 42.22°C
Answer: 42.22 °C
Describe an experiment to determine the specific heat capacity of a solid metal block using an electrical method. Include the measurements you would take and how you would use them to calculate the specific heat capacity.
Experimental Setup:
1. Insulate the metal block to reduce heat loss.
2. Insert a heater and a thermometer into the block.
3. Record the initial temperature (θ₁).
4. Turn on the heater and record the voltage (V) and current (I).
5. After a measured time (t), record the final temperature (θ₂).
Measurements:
* Mass of the block (m) in kg
* Initial temperature (θ₁) in °C
* Final temperature (θ₂) in °C
* Voltage (V) in V
* Current (I) in A
* Time (t) in s
Calculation:
1. Electrical energy supplied = V × I × t
2. Heat gained by the block = mc(θ₂ - θ₁)
3. Equate the two: V × I × t = mc(θ₂ - θ₁)
4. Rearrange to find c: c = (V × I × t) / (m × (θ₂ - θ₁))
*Explanation: This method uses electrical energy, which can be accurately measured, to heat a known mass of the solid. By measuring the temperature rise and knowing the energy input, the specific heat capacity can be determined.*
A student uses an immersion heater to heat 0.25 kg of water in a beaker. After 5 minutes (300 s) of heating with a 50 W heater, the temperature of the water increases from 20 °C to 35 °C. Calculate the specific heat capacity of water based on this experiment.
Formula:
* Energy supplied (E) = Power (P) × Time (t)
* Energy absorbed (E) = mass (m) × specific heat capacity (c) × temperature change (Δθ)
* c = E / (m × Δθ)
Working:
1. Calculate the energy supplied by the heater: E = P × t = 50 W × 300 s = 15000 J
2. Calculate the temperature change: Δθ = 35 °C - 20 °C = 15 °C
3. Calculate the specific heat capacity: c = 15000 J / (0.25 kg × 15 °C) = 4000 J kg⁻¹ °C⁻¹
Answer:
The specific heat capacity of water calculated from this experiment is 4000 J kg⁻¹ °C⁻¹.
*Explanation: This calculation uses the energy supplied to the water to determine the amount of heat required to raise the temperature of 1kg of water by 1°C.*
Key Questions: Specific heat capacity
Define specific heat capacity.
Specific heat capacity is the energy required per unit mass per unit temperature increase. It is the amount of energy needed to raise the temperature of 1 kg of a substance by 1 °C (or 1 K).
About Specific heat capacity (2.2.2)
These 8 flashcards cover everything you need to know about Specific heat capacity for your Cambridge IGCSE Physics (0625) exam. Each card is designed based on the official syllabus requirements.
What You'll Learn
- 1 Definitions - Key terms and their precise meanings that examiners expect
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After mastering Specific heat capacity, explore these related topics:
- 2.2.1 Thermal expansion of solids, liquids and gases - 6 flashcards
- 2.2.3 Melting, boiling and evaporation - 16 flashcards
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