1.7.2

Work

4 flashcards to master Work

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Key Concept Flip

A motor lifts a 0.5 kg mass vertically upwards through a distance of 1.2 m. Calculate the work done by the motor. Assume g = 10 N/kg.

Answer Flip

Work done = Force x Distance
Force = weight = mass x g = 0.5 kg x 10 N/kg = 5 N
Work done = 5 N x 1.2 m = 6.0 J
Answer: 6.0 J. The work done by the motor is equal to the energy transferred to the mass (gravitational potential energy).

Key Concept Flip

A car engine performs work to move the car forward. Explain how the work done by the engine relates to the energy of the car.

Answer Flip

The work done by the engine is equal to the energy transferred to the car. This energy transfer primarily increases the kinetic energy of the car, causing it to accelerate. Some of the energy transferred may also be converted into thermal energy due to friction within the engine and air resistance.

Key Concept Flip

A cyclist exerts a force of 52 N to travel 1.2 m. Calculate the work done by the cyclist.

Answer Flip

Formula: Work Done (W) = Force (F) × Distance (d)
Working:
W = 52 N × 1.2 m
W = 62.4 J
Answer: The work done is 62.4 J. Work done is the energy transferred when a force causes displacement.

Key Concept Flip

A crane lifts a metal block. Explain what is meant by 'work is done' in this situation.

Answer Flip

Work is done when a force causes a displacement. In this case, the crane exerts a force upwards on the metal block, and the block moves upwards. Because there is a force and a displacement in the same direction, work is done *on* the block by the crane. The energy is transferred from the crane (reducing its energy) to the block (increasing its gravitational potential energy).

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1.7.1 Energy 1.7.3 Energy resources

About Work (1.7.2)

These 4 flashcards cover everything you need to know about Work for your Cambridge IGCSE Physics (0625) exam. Each card is designed based on the official syllabus requirements.

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