The reactions of chlorine
Cambridge A-Level Chemistry (9701) · Unit 11: Group 17 · 11 flashcards
The reactions of chlorine is topic 11.4 in the Cambridge A-Level Chemistry (9701) syllabus , positioned in Unit 11 — Group 17 , alongside The chemical properties of the halogen elements and the hydrogen halides and Some reactions of the halide ions.
Marked as AS Level: examined at AS Level in Paper 1 (Multiple Choice), Paper 2 (AS Structured Questions) and Paper 3 (Advanced Practical Skills). The same content may also be assumed in Paper 4 (A Level Structured Questions).
The deck below contains 11 flashcards — 1 definition and 10 key concepts — covering the precise wording mark schemes reward. Use the definition card to lock down command-word answers (define, state), then move on to the concept and calculation cards to handle explain, describe, calculate and compare questions.
Some cards in this deck are on other syllabus topics: 12.1 Nitrogen and sulfur. Each card is labelled with its topic.
What the Cambridge 9701 syllabus says
2025-2027 syllabus, in our words · AS LevelWhat the syllabus expects you to be able to do in this topic, in plain English. For the exact wording, see the official syllabus (PDF).
- Describe the reactions of chlorine with cold aqueous NaOH and with hot aqueous NaOH, interpret them using changes in oxidation number, and recognise both as disproportionation.
- Explain, with an equation, how chlorine is used to purify water, including how it forms the active species HOCl and ClO⁻ that kill bacteria.
Also in this deck: 12.1 Nitrogen and sulfur
- Explain why nitrogen is so unreactive, referring to how strong its triple bond is and to its lack of polarity.
- Describe and explain: (a) why ammonia is a base, using Brønsted-Lowry theory; (b) the shape and bonding of the ammonium ion, NH₄⁺, and how it forms in an acid-base reaction; (c) how an acid-base reaction displaces ammonia from ammonium salts.
- State and explain where oxides of nitrogen come from, both naturally and from human activity, and how catalysts remove them from internal combustion engine exhaust gases.
- Understand that atmospheric NO and NO₂ may combine with unburned hydrocarbons, forming peroxyacetyl nitrate (PAN), one of the substances in photochemical smog.
- Describe how NO and NO₂ contribute to acid rain, both directly and by catalysing the oxidation of sulfur dioxide in the atmosphere.
Cambridge syllabus keywords to use in your answers
These are the official Cambridge 9701 terms tagged to this section. Mark schemes credit responses that use the exact term — weave them into your answers verbatim rather than paraphrasing.
Tips to avoid common mistakes in these topics
- › With hot NaOH(aq), chlorine disproportionates: 3Cl2 + 6NaOH → 5NaCl + NaClO3 + 3H2O.
- › For the formation of NaClO, specify that sodium hydroxide must be cold and in aqueous solution.
Topic 11.4 · The reactions of chlorine
Describe the reaction of chlorine with cold, dilute aqueous sodium hydroxide, including oxidation numbers.
Chlorine disproportionates: Cl₂ + 2NaOH → NaClO + NaCl + H₂O. The oxidation number of Cl changes from 0 in Cl₂ to +1 in NaClO and -1 in NaCl.
Topic 11.4 · The reactions of chlorine
Describe the reaction of chlorine with hot, concentrated aqueous sodium hydroxide, including oxidation numbers.
Chlorine disproportionates: 3Cl₂ + 6NaOH → NaClO₃ + 5NaCl + 3H₂O. The oxidation number of Cl changes from 0 in Cl₂ to +5 in NaClO₃ and -1 in NaCl.
Topic 11.4 · The reactions of chlorine
Explain how chlorine is used in water purification. Include the relevant equation(s).
Chlorine kills bacteria in water. Cl₂ + H₂O ⇌ HOCl + HCl. HOCl ⇌ H⁺ + ClO⁻. Both HOCl (hypochlorous acid) and ClO⁻ (hypochlorite ion) are active disinfecting agents.
Topic 12.1 · Nitrogen and sulfur
Explain why nitrogen is relatively unreactive.
Nitrogen gas (N₂) is unreactive due to the strong triple bond (N≡N), which requires a large amount of energy to break. Additionally, the molecule is non-polar.
Topic 12.1 · Nitrogen and sulfur
Explain the basicity of ammonia using the Brønsted-Lowry theory.
Ammonia (NH₃) is a Brønsted-Lowry base because it accepts a proton (H⁺) from an acid.
Topic 12.1 · Nitrogen and sulfur
Describe the structure of the ammonium ion (NH₄⁺) and its formation.
The ammonium ion (NH₄⁺) has a tetrahedral shape with the nitrogen atom at the center. It forms when ammonia (NH₃) accepts a proton (H⁺) from an acid, using its lone pair of electrons to form a coordinate (dative covalent) bond.
Topic 12.1 · Nitrogen and sulfur
Explain how ammonia can be displaced from ammonium salts.
Ammonia can be displaced from ammonium salts by a stronger base.
Topic 12.1 · Nitrogen and sulfur
Give examples of both natural and man-made occurrences of nitrogen oxides.
Natural occurrences: Lightning strikes causing nitrogen and oxygen in the air to react. Man-made occurrences: Internal combustion engines and industrial processes at high temperatures.
Topic 12.1 · Nitrogen and sulfur
Describe the catalytic removal of nitrogen oxides (NOx) from exhaust gases.
In a catalytic converter, a catalyst such as platinum, palladium or rhodium helps nitrogen monoxide react with carbon monoxide in the exhaust gases: 2NO + 2CO → N₂ + 2CO₂. NO is reduced to nitrogen while CO is oxidised to carbon dioxide.
Topic 12.1 · Nitrogen and sulfur
Describe how peroxyacetyl nitrate (PAN) is formed and its significance.
PAN is formed when atmospheric nitrogen oxides (NO and NO₂) react with unburned hydrocarbons. It is a component of photochemical smog and a secondary pollutant, causing respiratory and eye irritation.
Topic 12.1 · Nitrogen and sulfur
Explain the role of NO and NO₂ in the formation of acid rain.
Directly: NO is oxidised in air to NO₂, and NO₂ reacts with water and oxygen to form nitric acid: 4NO₂ + O₂ + 2H₂O → 4HNO₃. Catalytically: NO₂ oxidises SO₂ to SO₃ (NO₂ + SO₂ → NO + SO₃), and the NO is reoxidised (NO + ½O₂ → NO₂), so the nitrogen oxides are regenerated. The SO₃ then forms sulfuric acid: SO₃ + H₂O → H₂SO₄.
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The reactions of chlorine sits alongside these A-Level Chemistry decks in the same syllabus unit. Each uses the same spaced-repetition system, so progress in one informs the next.
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