SL & HL Wave Behaviour BETA C.5

Doppler Effect

The Doppler effect describes the observed change in frequency and wavelength of a wave when there is relative motion between the source and the observer. It serves as a vital tool across physics, from measuring the speeds of vehicles with sound and radar to determining the radial speeds of stars and galaxies from their spectral lines; HL students also treat the sound case quantitatively.

Part of IB Physics (2025-2030 syllabus) — Standard and Higher Level.

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Key points

  • When a wave source moves towards an observer, the observed wavelength decreases and the observed frequency increases, which corresponds to a blueshift in electromagnetic waves.
  • When a wave source moves away from an observer, the observed wavelength increases and the observed frequency decreases, representing a redshift in electromagnetic waves.
  • For light waves, the shift is symmetrical and depends solely on the relative velocity vv between the source and observer along the line of sight because the speed of light cc is constant in all reference frames.
  • HLFor sound waves, the physical mechanism depends on whether the source is moving (altering the physical wavelength in the medium) or the observer is moving (altering the relative speed at which wavefronts are intercepted).
  • Wavefront diagrams represent a moving source using eccentric circles that compress in the direction of motion, while a moving observer is drawn relative to concentric wavefronts emitted by a stationary source.
  • Astrophysicists analyze the Doppler shift of known stellar absorption or emission spectral lines to calculate the relative radial velocity of stars and distant galaxies.
  • Everyday technologies exploit the Doppler effect: radar speed guns compare the emitted and reflected microwave frequencies from a moving vehicle, and medical ultrasound uses the shift from moving blood cells to measure flow speed.

Subtopic by subtopic

The Doppler effect for sound and light

The Doppler effect is the change in the frequency and wavelength that an observer measures when the source of a wave and the observer move relative to one another. Motion that closes the gap squeezes successive wave crests together, so the observed frequency rises; motion that opens the gap stretches them apart, so the observed frequency falls.

You hear this every time an ambulance passes: the siren's pitch is higher while the vehicle approaches and drops noticeably the instant it goes by.

Sound and light behave differently in one important respect. Sound needs a material medium, so it matters physically whether the source or the observer is the one moving through the air. Light needs no medium and always travels at cc, so only the relative velocity along the line of sight matters.

For electromagnetic waves at IB level you use the approximation, valid whenever vcv \ll c:

Δff=Δλλvc\frac{\Delta f}{f} = \frac{\Delta \lambda}{\lambda} \approx \frac{v}{c}

  • Be able to state qualitatively how the observed frequency and wavelength change for approach and for recession.
  • Be able to apply the fractional-shift approximation to light and other electromagnetic waves.

Wavefront diagrams for a moving source or observer

A wavefront diagram shows circles of constant phase spreading outwards at the wave speed from the point where each crest was emitted. For a stationary source the circles are concentric.

For a moving source each successive circle is centred a little further along the path, so the pattern becomes eccentric: wavefronts bunch together ahead of the source (shorter wavelength, higher observed frequency) and spread out behind it (longer wavelength, lower observed frequency).

Think of the ripples around a swimming duck, crowded in front of it and stretched out behind.

When only the observer moves, the diagram looks completely different: the wavefronts remain concentric because the source and the medium are undisturbed, and the observer simply crosses those unchanging circles at a faster or slower rate.

In an exam you should be able to:

  • sketch at least three correctly spaced circular wavefronts and mark the source's velocity with an arrow;
  • identify from a given diagram whether the source is moving and in which direction;
  • explain the frequency heard at any labelled observer position using the wavefront spacing.

Doppler shift of spectral lines (astronomy)

Every element absorbs and emits light at fixed, well-known wavelengths, so the spectrum of a star or galaxy carries a built-in ruler. If a line that sits at λ0=656.3 nm\lambda_0 = 656.3\ \text{nm} in the laboratory appears at a longer wavelength, the object is receding (redshift); a shorter observed wavelength means it is approaching (blueshift).

The radial speed follows from:

vcΔλλ0v \approx c\,\frac{\Delta \lambda}{\lambda_0}

Astronomers use this to:

  • map the rotation of galaxies
  • detect the tiny wobble an orbiting planet induces in its star
  • measure the orbital speeds of binary star systems

While local movements of stars within our galaxy produce ordinary kinematic Doppler shifts caused by motion through space, the redshift observed in distant galaxies has a different primary origin.

Cosmological redshift is produced by the expansion of space itself: as space expands, the wavelengths of photons travelling through the universe are stretched along with it. This cosmological stretching is physically distinct from a classical Doppler shift, although both are evaluated using the same shift parameter z=Δλλ0z = \frac{\Delta \lambda}{\lambda_0} for non-relativistic recession speeds.

You must be able to:

  • read a rest wavelength and an observed wavelength from data or a spectrum
  • decide the direction of motion from the sign of the shift
  • calculate the radial speed

Quantitative Doppler effect for soundHL

At HL you must calculate observed sound frequencies, and the physical difference between a moving source and a moving observer is the key to choosing the right equation.

When a sound source moves through the air, it continues to emit wave crests that expand spherically about the point of emission. Because the source advances during each wave period TT, every new sphere starts further along the path. This mechanically compresses the physical wavelength in the medium ahead of the source to λ=λusT\lambda' = \lambda - u_s T. For approach this gives:

f=f(vvus)f' = f\left(\frac{v}{v - u_s}\right)

and f=f(vv+us)f' = f\left(\frac{v}{v + u_s}\right) for recession.

When instead an observer moves through a stationary wave field, the wavelength in the medium is unaffected. The frequency shift arises entirely because the wavefronts sweep past the observer at the relative speed vrel=v±uov_{\text{rel}} = v \pm u_o, so the observed frequency is:

f=vrelλ=f(v±uov)f' = \frac{v_{\text{rel}}}{\lambda} = f\left(\frac{v \pm u_o}{v}\right)

The plus sign applies for approach and the minus sign for recession.

A quick sanity check beats memorising signs: approach must always raise the frequency and recession must always lower it.

For example, a 900 Hz900\ \text{Hz} siren approaching at 28 m s128\ \text{m s}^{-1} is heard above 980 Hz980\ \text{Hz}, but only at about 830 Hz830\ \text{Hz} once it has passed.

Formulae

Δff=Δλλvc\frac{\Delta f}{f} = \frac{\Delta \lambda}{\lambda} \approx \frac{v}{c}

To calculate the fractional change in frequency or wavelength for electromagnetic waves when the relative speed vv is much less than the speed of light (vcv \ll c).

f=f(vvus)f' = f \left( \frac{v}{v - u_s} \right)HL

To calculate the observed frequency ff' of sound when the sound source is moving directly *towards* a stationary observer at speed usu_s in a medium where the speed of sound is vv.

f=f(vv+us)f' = f \left( \frac{v}{v + u_s} \right)HL

To calculate the observed frequency ff' of sound when the sound source is moving directly *away from* a stationary observer at speed usu_s.

f=f(v±uov)f' = f \left( \frac{v \pm u_o}{v} \right)HL

To calculate the observed frequency ff' of sound when an observer is moving at speed uou_o towards (++) or away from (-) a stationary sound source.

Definitions

Doppler effect
The change in the observed frequency and wavelength of a wave due to the relative motion between the wave source and the observer.
Redshift
The shifting of spectral lines towards longer wavelengths (lower frequencies) when an electromagnetic wave source moves away from the observer.
Blueshift
The shifting of spectral lines towards shorter wavelengths (higher frequencies) when an electromagnetic wave source moves towards the observer.
Wavefront
A continuous line or surface joining points of a wave that are in phase with one another; the direction of wave travel is perpendicular to the wavefront.
Radial velocity
The component of an object's velocity directed along the observer's line of sight; only this component produces a Doppler shift in the received waves.

Worked examples

1

A hydrogen emission line normally measured at a rest wavelength of λ0=656.3 nm\lambda_0 = 656.3\ \text{nm} in a terrestrial laboratory is observed in the spectrum of a distant galaxy at a wavelength of λ=661.2 nm\lambda = 661.2\ \text{nm}. (a) Deduce whether the galaxy is moving towards or away from Earth. (b) Calculate the radial speed of the galaxy relative to Earth.

  1. 1
    First, analyze the shift: since the observed wavelength λ=661.2 nm\lambda = 661.2\ \text{nm} is larger than the rest wavelength λ0=656.3 nm\lambda_0 = 656.3\ \text{nm}, the light has been redshifted. This indicates the galaxy is moving away from Earth.
  2. 2
    Calculate the change in wavelength: Δλ=λλ0=661.2 nm656.3 nm=4.9 nm\Delta \lambda = \lambda - \lambda_0 = 661.2\ \text{nm} - 656.3\ \text{nm} = 4.9\ \text{nm}.
  3. 3
    Use the Doppler shift equation for light: Δλλ0=vc\frac{\Delta \lambda}{\lambda_0} = \frac{v}{c}.
  4. 4
    Rearrange the equation to isolate the velocity: v=c×Δλλ0v = c \times \frac{\Delta \lambda}{\lambda_0}.
  5. 5
    Substitute the values into the equation, taking c3.00×108 m s1c \approx 3.00 \times 10^8\ \text{m s}^{-1}: v=(3.00×108 m s1)×4.9 nm656.3 nmv = (3.00 \times 10^8\ \text{m s}^{-1}) \times \frac{4.9\ \text{nm}}{656.3\ \text{nm}}.
  6. 6
    Perform the division and multiplication: v2.24×106 m s1v \approx 2.24 \times 10^6\ \text{m s}^{-1}.

Answer: 2.2×106 m s12.2 \times 10^6\ \text{m s}^{-1} away from Earth

2

A fire engine siren emits a continuous sound wave at a frequency of 900 Hz900\ \text{Hz}. The fire engine travels at a constant speed of 28.0 m s128.0\ \text{m s}^{-1} towards a stationary pedestrian. The speed of sound in air is 340 m s1340\ \text{m s}^{-1}. Calculate the frequency of the sound heard by the pedestrian: (a) as the fire engine approaches, and (b) after the fire engine has passed and is moving away.HL

  1. 1
    Identify the variables: source frequency f=900 Hzf = 900\ \text{Hz}, source speed us=28.0 m s1u_s = 28.0\ \text{m s}^{-1}, and sound speed v=340 m s1v = 340\ \text{m s}^{-1}.
  2. 2
    For part (a), the source is approaching. Use the moving source formula with a negative sign in the denominator to yield a higher frequency: f=f(vvus)f' = f \left( \frac{v}{v - u_s} \right).
  3. 3
    Substitute the values: f=900×(34034028.0)=900×340312980.8 Hzf' = 900 \times \left( \frac{340}{340 - 28.0} \right) = 900 \times \frac{340}{312} \approx 980.8\ \text{Hz}.
  4. 4
    For part (b), the source is receding. Use the moving source formula with a positive sign in the denominator to yield a lower frequency: f=f(vv+us)f' = f \left( \frac{v}{v + u_s} \right).
  5. 5
    Substitute the values: f=900×(340340+28.0)=900×340368831.5 Hzf' = 900 \times \left( \frac{340}{340 + 28.0} \right) = 900 \times \frac{340}{368} \approx 831.5\ \text{Hz}.

Answer: (a) 981 Hz981\ \text{Hz} as it approaches; (b) 832 Hz832\ \text{Hz} after it passes

3

A cyclist travels at a constant 7.00 m s17.00\ \text{m s}^{-1} along a straight road directly towards a stationary alarm that emits a steady tone of frequency 850 Hz850\ \text{Hz}. The speed of sound in air is 340 m s1340\ \text{m s}^{-1}. Calculate (a) the frequency the cyclist hears while approaching the alarm, and (b) the change in the frequency heard at the moment the cyclist passes the alarm and begins to move away from it.HL

  1. 1
    Identify the variables and the correct case: the observer moves while the source is stationary, with f=850 Hzf = 850\ \text{Hz}, uo=7.00 m s1u_o = 7.00\ \text{m s}^{-1} and v=340 m s1v = 340\ \text{m s}^{-1}, so use f=f(v±uov)f' = f \left( \frac{v \pm u_o}{v} \right).
  2. 2
    For part (a) the observer approaches the source, so take the plus sign: f=850×(340+7.00340)f' = 850 \times \left( \frac{340 + 7.00}{340} \right).
  3. 3
    Evaluate the approaching frequency: f=850×347340=867.5 Hzf' = 850 \times \frac{347}{340} = 867.5\ \text{Hz}.
  4. 4
    After passing, the observer recedes, so take the minus sign: f=850×(3407.00340)=850×333340=832.5 Hzf'' = 850 \times \left( \frac{340 - 7.00}{340} \right) = 850 \times \frac{333}{340} = 832.5\ \text{Hz}.
  5. 5
    For part (b), subtract the two observed frequencies to find the change heard at the moment of passing: Δf=867.5 Hz832.5 Hz=35.0 Hz\Delta f = 867.5\ \text{Hz} - 832.5\ \text{Hz} = 35.0\ \text{Hz}.

Answer: (a) 868 Hz868\ \text{Hz} while approaching; (b) the frequency drops by 35.0 Hz35.0\ \text{Hz} (from 868 Hz868\ \text{Hz} to 833 Hz833\ \text{Hz})

Common mistakes

  • ×Confusing the sign convention in the HL sound equations: remember that an approaching source must result in a higher frequency, meaning the denominator must be smaller (vusv - u_s). An approaching observer must also result in a higher frequency, meaning the numerator must be larger (v+uov + u_o).
  • ×Applying the classical moving-source sound formulas to light: because the speed of light is constant and does not rely on a physical medium, you must always use the approximation Δλλvc\frac{\Delta \lambda}{\lambda} \approx \frac{v}{c} (valid for vcv \ll c) for electromagnetic radiation.
  • ×Using the shifted observed wavelength λ\lambda in the denominator of the light shift formula instead of the rest/emission wavelength λ0\lambda_0. Always divide Δλ\Delta \lambda by the laboratory source value.
  • ×Sloppy drawing of wavefront diagrams: some students draw concentric circles when the source is moving. Ensure each circular wavefront has its center shifted sequentially along the path of motion.

Exam tips

  • When asked to **sketch** wavefront diagrams for a moving source, draw at least three circular wavefronts. Ensure they are bunched closely together on the side of motion and widely spaced on the opposite side, and clearly label the direction of the source's velocity.
  • To **distinguish** between the physical changes for sound: explicitly state that a moving source alters the actual wavelength in the medium, whereas a moving observer changes only the speed at which they cross unchanging physical wavelengths.
  • If a question requires you to **determine** stellar velocities from spectral graphs, always locate a specific emission peak, calculate the difference Δλ\Delta \lambda from its rest value, and verify whether the shift is positive (redshift) or negative (blueshift) before calculating the speed.
  • Watch your units in Paper 2: astronomical spectral wavelengths are often given in nanometers (nm\text{nm}) or micrometers (μm\mu\text{m}). Keep them in base meters when substituting into formulas alongside the speed of light c3.00×108 m s1c \approx 3.00 \times 10^8\ \text{m s}^{-1}.

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