1.5.1

Effects of forces

24 flashcards to master Effects of forces

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Key Concept Flip

A spring of original length 15.0 cm is hung vertically. A weight of 2.0 N is attached to the bottom of the spring, causing it to stretch to a new length of 17.0 cm. Calculate the extension of the spring.

Answer Flip

Formula: Extension = New Length - Original Length
Working: Extension = 17.0 cm - 15.0 cm = 2.0 cm
Answer: 2.0 cm
Explanation: The extension is the change in length of the spring due to the applied force (the weight).

Key Concept Flip

A student applies a force to a rubber band. Describe two ways the rubber band might change.

Answer Flip

1. The rubber band might increase in length (stretch). This is a change in size.
2. The rubber band might become thinner (decrease in cross-sectional area). This is a change in shape.

These changes are due to the force applied to the rubber band.

Key Concept Flip

A spring has an original length of 15.0 cm. When a load of 2.0 N is applied, its length increases to 18.0 cm. Calculate the extension of the spring. State your answer in metres.

Answer Flip

Extension = New Length - Original Length
Extension = 18.0 cm - 15.0 cm = 3.0 cm
Extension = 3.0 cm / 100 = 0.03 m

*Explanation: The extension is the difference between the spring's new length under load and its original length. Converting centimetres to metres requires dividing by 100.*

Key Concept Flip

Describe the experimental procedure to obtain a load-extension graph for a spring. Include the apparatus needed.

Answer Flip

1. Apparatus: Spring, ruler, clamp stand, weights (known masses), weight hanger.
2. Set Up: Clamp the spring vertically using the clamp stand.
3. Measure Original Length: Record the initial length of the spring without any load.
4. Add Load: Add weights to the weight hanger one at a time. For each weight added, record the new length of the spring.
5. Calculate Extension: For each weight, calculate the extension by subtracting the original length from the new length.
6. Repeat: Repeat the process for several different loads.
7. Plot Graph: Plot a graph of load (on the y-axis) against extension (on the x-axis).

Key Concept Flip

A car experiences a forward driving force of 4500 N and a resistive force due to air resistance and friction of 700 N. Calculate the resultant force acting on the car.

Answer Flip

Resultant force = Forward force - Resistive force
Resultant force = 4500 N - 700 N
Resultant force = 3800 N

The resultant force is the overall force acting on an object after considering all individual forces. It's the net effect of all forces combined.

Key Concept Flip

Explain why it is important to determine the resultant force acting on an object like a vehicle.

Answer Flip

Determining the resultant force is important because it indicates the net effect of all forces acting on the vehicle. The magnitude and direction of the resultant force directly determines the vehicle's acceleration (or deceleration) according to Newton's Second Law (F = ma). Knowing the resultant force allows us to predict the motion of the vehicle; a zero resultant force means the vehicle is either at rest or moving at constant velocity. A non-zero resultant force indicates the vehicle is accelerating or decelerating.

Key Concept Flip

A car is travelling at a constant speed of 20 m/s on a straight, level road. The driving force from the engine is 500 N. Calculate the resistive force acting on the car.

Answer Flip

The car is travelling at a constant speed in a straight line, therefore the resultant force is zero. This means the driving force and the resistive force are equal and opposite.

Resistive force = Driving force = 500 N

Key Concept Flip

Explain, in terms of forces, why a hockey puck sliding on smooth ice will eventually come to rest.

Answer Flip

The hockey puck will come to rest because of a resultant force acting on it. Even though the ice is smooth, there is still friction (a resistive force) between the puck and the ice. This friction opposes the motion of the puck. Because there are no other forces to balance the friction, the resultant force is non-zero, and this causes the puck to decelerate until it stops.

Key Concept Flip

A 2.0 kg toy car is travelling at a constant speed of 3.0 m/s in a straight line. A constant resultant force of 0.5 N is applied to the car in the direction perpendicular to its motion. Calculate the magnitude of the car's change in velocity after 4.0 seconds due to this force.

Answer Flip

1. Calculate acceleration:
* *F* = *ma*
* 0.5 N = 2.0 kg * *a*
* *a* = 0.25 m/s²

2. Calculate the change in velocity:
* *v* = *u* + *at*
* *v* = 0 + 0.25 m/s² * 4.0 s
* *v* = 1.0 m/s

Answer: The magnitude of the car's change in velocity is 1.0 m/s. The resultant force causes an acceleration perpendicular to the initial velocity, changing the direction and hence the velocity of the car.

Key Concept Flip

A bicycle is travelling along a straight, horizontal road. State two ways in which a resultant force acting on the bicycle could change its velocity.

Answer Flip

1. Change in speed: The resultant force could cause the bicycle to speed up (increase its velocity) or slow down (decrease its velocity).

2. Change in direction: The resultant force could cause the bicycle to change its direction, even if its speed remains constant. Note: A change in direction *is* a change in velocity, even if the speed is constant.

Key Concept Flip

A spring extends by 0.20 m when a force of 5.0 N is applied. Calculate the spring constant, k.

Answer Flip

Formula: k = F/x
Substitution: k = 5.0 N / 0.20 m
Answer: k = 25 N/m
Explanation: The spring constant is the force required per unit extension. A larger spring constant indicates a stiffer spring.

Key Concept Flip

A spring has a spring constant of 40 N/m. State what this value represents.

Answer Flip

The spring constant of 40 N/m means that a force of 40 N is required to extend (or compress) the spring by 1 meter.

Definition Flip

Define the term 'limit of proportionality' in the context of a load-extension graph for a spring.

Answer Flip

The limit of proportionality is the point on a load-extension graph beyond which Hooke's Law (Load ∝ extension) is no longer obeyed. Beyond this point, the graph is no longer a straight line, indicating that the extension is not directly proportional to the applied load.

Key Concept Flip

A spring is subjected to increasing loads. The following load and extension values were recorded: (0N, 0cm), (1N, 0.5cm), (2N, 1.0cm), (3N, 1.5cm), (4N, 2.0cm), (5N, 2.4cm). State which load represents the approximate limit of proportionality. Explain your reasoning.

Answer Flip

The approximate limit of proportionality is 4N.

Explanation: Up to 4N, the extension increases proportionally with the load (for every 1N increase in load, the extension increases by 0.5cm). After 4N, the extension only increases by 0.4cm. This indicates that the relationship is no longer linear, and the limit of proportionality has been exceeded.

Key Concept Flip

A car of mass 800 kg accelerates at 2.5 m/s². Calculate the resultant force acting on the car.

Answer Flip

F = ma
F = 800 kg * 2.5 m/s²
F = 2000 N
The resultant force is 2000 N. This force causes the car to accelerate.

Key Concept Flip

A toy car accelerates in a straight line. Explain why a resultant force must be acting on the car.

Answer Flip

According to Newton's Second Law (F=ma), an object accelerates only if there is a resultant force acting on it. If the forces are balanced, the object will either remain at rest or continue moving at a constant velocity. Therefore, a resultant force is necessary for acceleration to occur.

Key Concept Flip

A toy car of mass 0.2 kg is moving in a circle of radius 0.5 m at a constant speed. The force providing the circular motion is 0.8 N. If the force is increased to 1.6 N, what will the new speed of the car be, assuming the radius remains constant?

Answer Flip

Formula: F = mv²/r

Initial: 0.8 = (0.2 * v₁²)/0.5 => v₁² = (0.8 * 0.5)/0.2 = 2 => v₁ = √2 ≈ 1.41 m/s

Final: 1.6 = (0.2 * v₂²)/0.5 => v₂² = (1.6 * 0.5)/0.2 = 4 => v₂ = √4 = 2 m/s

Answer: The new speed will be 2 m/s. Increasing the force increases the speed, keeping the radius constant.

Key Concept Flip

A satellite orbits the Earth in a circular path due to gravity. Explain what happens to the satellite's orbital radius if the gravitational force acting on it increases, assuming its speed and mass remain constant.

Answer Flip

The satellite's orbital radius will decrease. Since the centripetal force (gravitational force in this case) is directly proportional to the square of the speed and inversely proportional to the radius (F = mv²/r), if the force increases while the speed and mass remain constant, the radius must decrease to maintain the equality. A stronger gravitational pull forces the satellite into a tighter orbit.

Key Concept Flip

A wooden block is dragged across a rough concrete surface at a constant speed. The force applied to pull the block is 5.0 N. Calculate the frictional force between the block and the surface.

Answer Flip

Frictional force = Applied Force (since constant speed, forces are balanced)
Frictional Force = 5.0 N

Explanation: When an object moves at a constant speed, the net force acting on it is zero. Therefore, the frictional force must be equal and opposite to the applied force.

Key Concept Flip

Explain why a car's tires get warm after a long drive.

Answer Flip

As the tires roll on the road surface, there is a force of friction between the tire and the road. This friction opposes the motion of the tire. The constant rubbing between the tire and the road converts some of the kinetic energy into thermal energy due to the work done by the frictional force. This thermal energy causes the tires to heat up.

Key Concept Flip

A small ball is dropped into a container of oil. The ball has a weight of 0.45 N. As the ball accelerates through the oil, a drag force acts upwards on the ball. At one point, the drag force is 0.2 N. Calculate the resultant force acting on the ball at this point.

Answer Flip

Resultant force = Weight - Drag Force
Resultant force = 0.45 N - 0.2 N
Resultant force = 0.25 N

Explanation: The resultant force is the vector sum of all forces acting on the ball. Since weight acts downwards and drag upwards, we subtract drag from weight.

Key Concept Flip

Explain, in terms of forces, why a stone falls faster through air than through water.

Answer Flip

The stone experiences air resistance (drag) as it falls through air and water. Water is more viscous than air; thus the drag force exerted by water on the stone is greater than the drag force exerted by air. The resultant force on the stone is smaller when falling in water, thus it accelerates less and falls slower than when falling in air.

Key Concept Flip

A car is travelling at a constant velocity. The driving force of the engine is 800 N. Calculate the size of the air resistance acting on the car.

Answer Flip

Air resistance = Driving Force (since constant velocity, forces are balanced)
Air resistance = 800 N

Explanation: At constant velocity, acceleration is zero. Therefore, the net force is zero. This means the air resistance must be equal and opposite to the driving force.

Key Concept Flip

Explain, in terms of forces, why a parachute slows down a sky diver.

Answer Flip

The parachute increases the surface area exposed to the air. This significantly increases the air resistance (drag force) acting upwards on the sky diver. The increased air resistance is now greater than the sky diver's weight (force due to gravity). This produces a resultant upward force, causing the sky diver to decelerate (slow down).

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1.4 Density 1.5.2 Turning effect of forces

Key Questions: Effects of forces

Define the term 'limit of proportionality' in the context of a load-extension graph for a spring.

The limit of proportionality is the point on a load-extension graph beyond which Hooke's Law (Load ∝ extension) is no longer obeyed. Beyond this point, the graph is no longer a straight line, indicating that the extension is not directly proportional to the applied load.

About Effects of forces (1.5.1)

These 24 flashcards cover everything you need to know about Effects of forces for your Cambridge IGCSE Physics (0625) exam. Each card is designed based on the official syllabus requirements.

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