Gases and the absolute scale of temperature
6 flashcards to master Gases and the absolute scale of temperature
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A sealed container of fixed volume contains a gas at a temperature of 27°C and a pressure of 1.0 x 10⁵ Pa. The gas is heated to a temperature of 327°C. Calculate the new pressure of the gas, assuming the volume remains constant.
1. Convert Temperatures to Kelvin:
T₁ = 27°C + 273 = 300 K
T₂ = 327°C + 273 = 600 K
2. Apply the Pressure Law (P₁/T₁ = P₂/T₂):
(1.0 x 10⁵ Pa) / 300 K = P₂ / 600 K
3. Solve for P₂:
P₂ = (1.0 x 10⁵ Pa * 600 K) / 300 K
P₂ = 2.0 x 10⁵ Pa
*Explanation: The pressure increases because the increased temperature gives the gas particles more kinetic energy, causing them to collide with the container walls more frequently and with greater force.*
Describe, in terms of particles, how increasing the volume of a fixed mass of gas at constant temperature affects its pressure.
When the volume is increased, the gas particles have more space to move around. This means they collide with the walls of the container less frequently. As the number of collisions per second decreases, the pressure decreases. The average kinetic energy and speed of the particles remains the same because the temperature is constant.
Calculate the temperature in Kelvin if the temperature in Celsius is 27°C.
T(K) = θ(°C) + 273
T(K) = 27 + 273
T(K) = 300 K
Explanation: To convert from Celsius to Kelvin, add 273 to the Celsius temperature.
Explain why it is important to use the Kelvin scale when performing calculations involving the pressure of a gas.
The Kelvin scale is an absolute temperature scale, meaning that 0 K corresponds to absolute zero, the point at which all molecular motion ceases. If Celsius were used, calculations could produce negative pressures (e.g. volume and pressure are directly proportional in kelvin, but are not in celsius). Also, using Celsius would produce errors in calculations involving the gas laws, because the relationships between variables such as pressure, volume, and temperature are only directly proportional when temperature is expressed in Kelvin.
A gas occupies a volume of 2.0 m³ at a pressure of 1.0 x 10⁵ Pa. If the temperature of the gas remains constant, calculate the new pressure if the volume is reduced to 0.9 m³.
Formula: P₁V₁ = P₂V₂
Working: P₂ = (P₁V₁) / V₂ = (1.0 x 10⁵ Pa * 2.0 m³) / 0.9 m³ = 2.22 x 10⁵ Pa
Answer: 2.22 x 10⁵ Pa. The pressure increases because the same number of gas molecules are now in a smaller space, leading to more frequent collisions with the container walls.
Explain, in terms of the behaviour of gas molecules, why the pressure of a fixed mass of gas at constant temperature increases when its volume is decreased.
When the volume decreases, the gas molecules have less space to move in. This means they collide more frequently with the walls of the container. The increased frequency of collisions results in a greater force exerted on the walls per unit area, hence the pressure increases. The temperature is constant, therefore the average kinetic energy of the molecules remains constant.
About Gases and the absolute scale of temperature (2.1.3)
These 6 flashcards cover everything you need to know about Gases and the absolute scale of temperature for your Cambridge IGCSE Physics (0625) exam. Each card is designed based on the official syllabus requirements.
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