6.1.2

The Solar System

20 flashcards to master The Solar System

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Key Concept Flip

Describe the general structure of our Solar System, identifying its main components and their typical locations.

Answer Flip

The Solar System consists of a central star, the Sun, orbited by eight named planets: Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune. There are also minor planets, including dwarf planets like Pluto and asteroids mostly located in the asteroid belt between Mars and Jupiter. Planets are orbited by moons. Smaller Solar System bodies like comets also exist.

Key Concept Flip

State three different types of celestial bodies, other than the eight major planets, that are found in our Solar System.

Answer Flip

1. Moons: Natural satellites that orbit planets.
2. Asteroids: Rocky bodies that orbit the Sun, primarily found in the asteroid belt between Mars and Jupiter.
3. Comets: Icy bodies that orbit the Sun, often with highly elliptical orbits.

Key Concept Flip

Explain why the planets nearest the Sun are rocky and small, while the planets furthest from the Sun are gaseous and large. Refer to the accretion model of Solar System formation in your answer.

Answer Flip

During the formation of the Solar System, the inner region near the Sun was hotter. This heat prevented lighter gases like hydrogen and helium from condensing into solids. Only heavier elements like iron and rock could solidify at these temperatures. Therefore, the inner planets formed from these heavier materials, resulting in small, rocky planets. Further from the Sun, it was cooler, allowing lighter gases to condense into solids. These gases, along with some rock and ice, accreted to form large, gaseous planets. The accretion model depends on gravity to pull together interstellar gas and dust, which contained many elements, into a rotating cloud that formed an accretion disk.

Key Concept Flip

State three key aspects of the accretion model for the formation of the Solar System that explain the different characteristics of inner and outer planets.

Answer Flip

1. Gravity: Gravity is responsible for pulling the interstellar gas and dust together.
2. Presence of many elements: The interstellar cloud contained a variety of elements, leading to different compositions of planets.
3. Rotation and accretion disk: The rotation of the cloud led to the formation of an accretion disk, where material collided and stuck together, forming planetesimals.

Key Concept Flip

State the shape of the orbits of planets, minor planets, and comets in our solar system. Where is the Sun located with respect to these orbits?

Answer Flip

The orbits are elliptical.
The Sun is located at one focus of the ellipse, not at the centre, except when the orbit is approximately circular.

Key Concept Flip

Explain why the speed of a comet changes as it orbits the Sun in its elliptical orbit.

Answer Flip

As the comet approaches the Sun, its gravitational potential energy decreases and its kinetic energy increases, causing it to speed up. Conversely, as the comet moves away from the Sun, its gravitational potential energy increases and its kinetic energy decreases, causing it to slow down. This is due to the Sun being at one focus of the ellipse, not the center.

Key Concept Flip

The planet Xylo has an orbital radius of 2.0 x 10^11 m and an orbital period of 3.6 x 10^8 s. The planet Yonder has an orbital radius of 5.0 x 10^11 m. Calculate the orbital period of Yonder.

Answer Flip

1. Apply Kepler's Third Law: (T1/T2)^2 = (R1/R2)^3
2. Rearrange for T2: T2 = T1 * sqrt((R2/R1)^3)
3. Substitute values: T2 = (3.6 x 10^8 s) * sqrt((5.0 x 10^11 m / 2.0 x 10^11 m)^3)
4. Calculate: T2 = (3.6 x 10^8 s) * sqrt((2.5)^3) = (3.6 x 10^8 s) * 3.95 = 1.42 x 10^9 s
Answer: 1.42 x 10^9 s. Kepler's Third Law allows us to relate orbital period and radius.

Key Concept Flip

Planet A has a significantly higher average surface temperature than Planet B, despite having a similar uniform gravitational field strength at the surface. Suggest two reasons why Planet A is hotter than Planet B, based on planetary data.

Answer Flip

1. Shorter orbital distance: Planet A may be closer to the star, receiving more solar radiation.
2. Presence of a significant atmosphere: Planet A may have a dense atmosphere with a strong greenhouse effect, trapping more heat.

Key Concept Flip

Planet A has a mass of 5.0 x 10<sup>24</sup> kg and a radius of 6.0 x 10<sup>6</sup> m. Planet B has a mass of 1.0 x 10<sup>25</sup> kg and a radius of 1.2 x 10<sup>7</sup> m. Calculate the ratio of the gravitational field strength at the surface of Planet B to the gravitational field strength at the surface of Planet A. (Assume g is proportional to M/r<sup>2</sup>)

Answer Flip

g ∝ M/r2
Ratio = (MB/rB2) / (MA/rA2)
Ratio = (1.0 x 1025 kg / (1.2 x 107 m)2) / (5.0 x 1024 kg / (6.0 x 106 m)2)
Ratio = (1.0 x 1025 / 1.44 x 1014) / (5.0 x 1024 / 3.6 x 1013)
Ratio = 6.94 / 13.89
Ratio = 0.50
The ratio of gravitational field strength on Planet B to Planet A is 0.50. This means the gravitational field strength is half as strong on Planet B as it is on Planet A.

Key Concept Flip

Describe how the strength of the gravitational field around a planet changes as the distance from the planet increases. Explain why this happens.

Answer Flip

The strength of the gravitational field decreases as the distance from the planet increases.

Explanation: Gravitational force is inversely proportional to the square of the distance between the planet and the object. This means that as the distance increases, the gravitational force, and therefore the gravitational field strength, decreases rapidly. The field lines become more spread out further from the planet, representing a weaker force per unit mass.

Key Concept Flip

The average distance between Mars and the Sun is 228 million kilometers. Calculate the time, in minutes, it takes for light to travel from the Sun to Mars. The speed of light is 3.0 x 10^8 m/s.

Answer Flip

1. Convert distance to meters:
Distance = 228,000,000 km = 228,000,000,000 m = 2.28 x 10^11 m

2. Use the formula: time = distance / speed
time = (2.28 x 10^11 m) / (3.0 x 10^8 m/s) = 760 s

3. Convert seconds to minutes:
time = 760 s / 60 s/min = 12.67 minutes

Answer: 12.67 minutes (This calculation uses the distance and speed of light to find the travel time of light).

Key Concept Flip

Explain why there is a time delay for radio signals to reach Earth from a spacecraft orbiting Neptune, even though radio waves travel at the speed of light.

Answer Flip

Although radio waves travel at the speed of light, the immense distances involved in space travel cause a noticeable time delay. The greater the distance, the longer it takes for the signal to travel. Neptune is very far from Earth, therefore, the radio signal needs a significant amount of time to cover that large distance. This delay can be calculated using the formula: time = distance / speed.

Key Concept Flip

The mass of the Sun is approximately 330,000 times the mass of the Earth, and about 1000 times the mass of Jupiter. Explain why the planets in our solar system orbit the Sun and not another planet.

Answer Flip

The Sun contains the vast majority of the mass in the Solar System.

This creates a large gravitational force towards the Sun.

The gravitational force is what keeps the planets in orbit. Since the Sun's gravitational pull is so much greater, all planets orbit it.

Key Concept Flip

State why the planets in our Solar System orbit the Sun.

Answer Flip

The planets orbit the Sun due to the Sun's immense mass creating a strong gravitational force, which attracts all the planets.

Key Concept Flip

State the force that keeps the Earth in orbit around the Sun.

Answer Flip

The force is the gravitational attraction of the Sun. This is the force of gravity acting between the Earth and the Sun.

Key Concept Flip

Describe how the gravitational attraction of the Sun keeps a planet in orbit. Use the term 'centripetal force' in your answer.

Answer Flip

The Sun's gravitational attraction provides the centripetal force needed to keep the planet moving in a circular path around the Sun. This force constantly pulls the planet towards the Sun, preventing it from moving in a straight line and causing it to orbit.

Key Concept Flip

The Earth orbits the Sun at a distance of 1.5 x 10^11 m and has an orbital speed of 3.0 x 10^4 m/s. A hypothetical planet orbits the Sun at a distance of 6.0 x 10^11 m. Assuming a circular orbit, calculate the orbital speed of this hypothetical planet.

Answer Flip

1. *Formula*: v = √(GM/r), where v = orbital speed, G = gravitational constant, M = mass of Sun, r = orbital radius
2. *Ratio*: Since GM is constant, v ∝ √(1/r). Therefore, v₂/v₁ = √(r₁/r₂)
3. *Calculation*: v₂ = v₁ * √(r₁/r₂) = (3.0 x 10^4 m/s) * √((1.5 x 10^11 m)/(6.0 x 10^11 m)) = (3.0 x 10^4 m/s) * √(0.25) = (3.0 x 10^4 m/s) * 0.5 = 1.5 x 10^4 m/s

*Answer*: The orbital speed of the hypothetical planet is 1.5 x 10^4 m/s. This is because a larger orbital radius means a weaker gravitational force at that radius, hence a lower orbital speed is required to maintain a stable orbit.

Key Concept Flip

State how the strength of the Sun's gravitational field and the orbital speed of planets change as the distance from the Sun increases.

Answer Flip

1. *Gravitational Field Strength*: The strength of the Sun's gravitational field decreases as the distance from the Sun increases.
2. *Orbital Speed*: The orbital speed of planets decreases as the distance from the Sun increases.

*Explanation*: Gravitational force weakens with distance, requiring lower speeds to maintain a stable orbit.

Key Concept Flip

Explain why a comet in an elliptical orbit around the Sun moves faster when it is closer to the Sun.

Answer Flip

As the comet moves closer to the Sun, its gravitational potential energy decreases. Due to the conservation of energy, this decrease in potential energy is converted into kinetic energy. An increase in kinetic energy means an increase in the comet's speed. Therefore, the comet moves faster when closer to the Sun. Formula: Total Energy = Kinetic Energy + Potential Energy. Decrease in Potential Energy = Increase in Kinetic Energy.

Key Concept Flip

A satellite is in an elliptical orbit around a planet. At its furthest point from the planet, its speed is 5000 m/s and its gravitational potential energy is -2.0 x 10^9 J. At its closest point, its gravitational potential energy is -4.0 x 10^9 J. Assuming no energy is lost, calculate the satellite's speed at its closest point. The satellite's mass is 1000 kg.

Answer Flip

1. Calculate the change in potential energy: ΔPE = -4.0 x 10^9 J - (-2.0 x 10^9 J) = -2.0 x 10^9 J
2. This decrease in PE is equal to the increase in KE: ΔKE = 2.0 x 10^9 J
3. Calculate the initial kinetic energy: KE_initial = 0.5 * m * v^2 = 0.5 * 1000 kg * (5000 m/s)^2 = 1.25 x 10^10 J
4. Calculate the final kinetic energy: KE_final = KE_initial + ΔKE = 1.25 x 10^10 J + 2.0 x 10^9 J = 1.45 x 10^10 J
5. Calculate the final speed: v = √(2 * KE_final / m) = √(2 * 1.45 x 10^10 J / 1000 kg) = 5385 m/s. The satellite's speed at its closest point is 5385 m/s. The conversion of potential energy to kinetic energy causes the speed increase.

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6.1.1 The Earth 6.2.1 The Sun as a star

About The Solar System (6.1.2)

These 20 flashcards cover everything you need to know about The Solar System for your Cambridge IGCSE Physics (0625) exam. Each card is designed based on the official syllabus requirements.

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