The Earth
8 flashcards to master The Earth
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Explain why we experience day and night on Earth, linking your explanation to the Earth's rotation. (1)
The Earth rotates on its axis. As a location rotates into sunlight, it experiences day. As it rotates away from sunlight, it experiences night.
Suggest why the apparent daily movement of the Sun across the sky is different in the Northern and Southern Hemispheres. (1)
The Earth's axis is tilted relative to its orbit around the Sun. This tilt causes different hemispheres to be exposed to different amounts of direct sunlight throughout the year, altering the apparent path of the Sun.
Explain why the Earth experiencing 365 days in its orbit around the Sun results in the cyclical changes we observe as seasons. (1 mark)
The Earth's axial tilt, coupled with its 365-day orbit, causes different hemispheres to be closer to the Sun at different times, leading to seasonal changes (1 mark).
Suggest how a planet's orbital period around its star impacts the duration and frequency of its seasons, given the Earth's orbital period is 365 days. (1 mark)
A shorter orbital period would lead to more frequent and potentially shorter seasons. A longer period would mean fewer, but potentially longer seasons (1 mark).
Explain why the Moon's phases, such as full moon or new moon, occur approximately once a month (every 29.5 days). (1)
The Moon orbits the Earth approximately once a month. Different amounts of the moon are illuminated by the sun in this periodic orbit. (1)
Suggest why calendars are often based on cycles of roughly 30 days. (1)
The Moon orbits the Earth in approximately one month (29.5 days), giving a natural cycle for tracking time. (1)
Define average orbital speed, stating the meaning of each symbol in the equation used to calculate it.
Average orbital speed is the distance travelled in one orbit divided by the orbital period. V = 2πr/T, where V is average orbital speed, r is the average radius of the orbit, and T is the orbital period.
The Earth orbits the Sun with an average radius of 1.5 x 10¹¹ m and a period of 3.16 x 10⁷ s. Calculate the Earth's average orbital speed.
V = 2πr/T
V = 2π(1.5 x 10¹¹ m) / (3.16 x 10⁷ s)
V = 2.98 x 10⁴ m/s
The average orbital speed is calculated using the formula, substituting given values and solving.
Key Questions: The Earth
Define average orbital speed, stating the meaning of each symbol in the equation used to calculate it.
Average orbital speed is the distance travelled in one orbit divided by the orbital period. V = 2πr/T, where V is average orbital speed, r is the average radius of the orbit, and T is the orbital period.
About The Earth (6.1.1)
These 8 flashcards cover everything you need to know about The Earth for your Cambridge IGCSE Physics (0625) exam. Each card is designed based on the official syllabus requirements.
What You'll Learn
- 1 Definitions - Key terms and their precise meanings that examiners expect
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After mastering The Earth, explore these related topics:
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